Frozen CO2 or dry ice is different from CO2 gas in the atmosphere because it has
2 answers:
Answer: Option (b) is the correct answer.
Explanation:
Dry ice is the solid form of carbon dioxide whereas carbon dioxide gas present in the atmosphere is present in gaseous phase.
Also it is known that in solids, particles are held together tightly due to strong intermolecular forces of attraction. As a result, solid substances have fixed shape and volume.
On the other hand, in gases particles are held by weak intermolecular forces due to which they are far apart from each other. As a result, they do not hace any fixed shape.
Hence, we can conclude that frozen or dry ice is different from
gas in the atmosphere because it has a fixed shape.
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Answer :
The oxidation state of oxygen (O) in is, (+2)
The oxidation state of carbon (C) in is, (+2)
The oxidation state of nitrogen (N) in is, (-3)
Explanation :
Oxidation number : It represent the number of electrons lost or gained by the atoms of an element in a compound.
Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.
When the atoms are present in their elemental state then the oxidation number will be zero.
Rules for Oxidation Numbers :
The oxidation number of a free element is always zero.
The oxidation number of a monatomic ion equals the charge of the ion.
The oxidation number of Hydrogen (H) is +1, but it is -1 in when combined with less electronegative elements.
The oxidation number of oxygen (O) in compounds is usually -2, but it is -1 in peroxides.
The oxidation number of a Group 1 element in a compound is +1.
The oxidation number of a Group 2 element in a compound is +2.
The oxidation number of a Group 17 element in a binary compound is -1.
The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.
(a) The given compound is,
Let the oxidation state of 'O' be, 'x'
The oxidation state of oxygen (O) in is, (+2)
(b) The given compound is,
Let the oxidation state of 'C' be, 'x'
The oxidation state of carbon (C) in is, (+2)
(c) The given compound is,
Let the oxidation state of 'N' be, 'x'
The oxidation state of nitrogen (N) in is, (-3)