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Lyrx [107]
3 years ago
10

I need help Please i will give brainlist Please and thank you ​

Mathematics
2 answers:
tangare [24]3 years ago
4 0

Answer:

all I know is the answer for 5 so it is 2.0

Step-by-step explanation:

Dovator [93]3 years ago
4 0

Answer:

4. 79.17%

5. 2.5

Step-by-step explanation:

4.  Q3 - Q1 = 4.75 - 0 = 4.75

      \frac{4.75}{6} *100 = 79.17

5.  Q3 - Q1 = 4.75 - 2.25 = 2.5

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selena walks home to school each mm morning and back home each afternoon. altogether she walks 2/3 mile wach day. how far does s
LenaWriter [7]

Answer:



One days trip of to school from home and back home from school is 2/3 of a mile. We want to know how far it is to school from her house.

To solve this, we simply need to take half of the total distance (2/3)

\frac{2}{3} / 2

Next, we need to turn the 2 into a fraction. Every whole number can be made into a fraction by putting it over 1.

\frac{2}{3} / \frac{2}{1}

Because we are dividing, we need to invert the second fraction and then multiply.

\frac{2}{3} * \frac {1}{2}

Next, we multiply the top of the first fraction by the top of the second and the bottom of the first fraction by the bottom of the second.

\frac{2}{6}

Once you reduce, you get:

\frac{1}{3}

4 0
3 years ago
7. Which of the following equations are
Anuta_ua [19.1K]
C and E are the right ones
6 0
3 years ago
yall do u want me to fail? if no plz answer this question: is 92.35 equal to (9 × 100) + (2 ×10) + (3 × 110) + (5 × 1100)
schepotkina [342]

Answer:

no of course its not.

Step-by-step explanation:

(9 × 100) + (2 ×10) + (3 × 110) + (5 × 1100)

900+20+330+5500

1800

92.35 isnt equal to 1800

6 0
3 years ago
These dot plots show the ages (in years) for a sample of two types of fish.
drek231 [11]

*Select two choices: one for the centers and one for the spreads.

A. Centers: The sharks have a lower median age than the koi

B. Spreads: The ages of the koi are more spread out.

C. Centers: The sharks have a greater median age than the koi.

D. Spreads: The ages of the sharks are more spread out

(See attachement for diagram)

Answer:

A. and B.

Step-by-step explanation:

Measure of center that can be used in stating the differences between Koi and Shark is the median.

Examining the dot plot, the median age for Sharks is 20.

The median age for Koi is the 14th data point, which is 40.

Thus, for the center, we can conclude that Sharks has a lower median age than Koi.

For the spread, the larger the range, the more spread out the data are.

Thus:

Range for Sharks = 30 - 10 = 20

Range for Koi = 70 - 25 = 45

Therefore, we can conclude that the ages of Koi are more spread out.

5 0
3 years ago
Find the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis. Verify y
mariarad [96]

Answer:

the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis is;

\frac{\pi }{2}  [e^2 - 1 ]  or 10.036

Step-by-step explanation:

Given the data in the question;

y = y = e^{(x - 1 ), y = 0, x = 1, x = 2.

Now, using the integration capabilities of a graphing utility

y = y = e_2}^{(x - 1 )_, y = 0

Volume = \pi \int\limits^2_1 ( e^{x-1)^2} - (0)^2 dx

Volume = \pi \int\limits^2_1 ( e^{x-1)^2  dx

Volume = \pi \int\limits^2_1 e^{2x-2}dx

Volume = \frac{\pi }{e^2} \int\limits^2_1 e^{2x}dx

Volume = \frac{\pi }{e^2}  [\frac{e^{2x}}{2}]^2_1

Volume = \frac{\pi }{2e^2}  [e^4 - e^2 ]  

Volume = \frac{\pi }{2}  [e^2 - 1 ]  or 10.036

Therefore, the volume of the solid generated by revolving the region bounded by the graphs of the equations about the x-axis is;

\frac{\pi }{2}  [e^2 - 1 ]  or 10.036

   

3 0
3 years ago
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