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Georgia [21]
3 years ago
7

yall do u want me to fail? if no plz answer this question: is 92.35 equal to (9 × 100) + (2 ×10) + (3 × 110) + (5 × 1100)

Mathematics
1 answer:
schepotkina [342]3 years ago
6 0

Answer:

no of course its not.

Step-by-step explanation:

(9 × 100) + (2 ×10) + (3 × 110) + (5 × 1100)

900+20+330+5500

1800

92.35 isnt equal to 1800

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Sandra notices a fourth racer called the Whirlwind. Its poster says it covers 1232 yards in 180 seconds. She wants to compare th
Daniel [21]

Answer:

6.8yards/seconds

Step-by-step explanation:

Speed = Distance/Time

Given the following

Distance covered = 1232 yards

Time taken = 180 seconds

Substitute to get the speed

Speed  = 1232/180

Speed  = 6.84

Hence whirlwind's speed in yards per seconds to the nearest tenth is 6.8yards/seconds

4 0
2 years ago
Jason complete 5/8 of his test and 10/25 of his homework. What fraction of his homework does he still need to complete?
sineoko [7]

Answer:

3/4

Step-by-step explanation:

Because the total homework would be 25/25

\frac{25}{25}-\frac{10}{25} =\frac{15}{25}

15/20 can be reduced to 3/4

4 0
3 years ago
If 1 ft = 1.894 x 10​ -4​miles, convert 20.0 inches to miles
Yakvenalex [24]

Answer:

3.1567 * 10^-4 miles

Step-by-step explanation:

1 ft = 1.894 * 10^-4 miles , so

1 inch = 1.894 * 10^-4 / 12  miles

= 0.15783 * 10^-4

= 1.5783* 10^-5 miles  ( in scientific form).

Multiplying this by 20 we get

31.567 * 10^-5

= 3.1567 * 10^-4 miles.

3 0
2 years ago
Find the percent change from 70 to 42.
Evgen [1.6K]

Answer:

It decreased by 40%

Step-by-step explanation:

Percent change = 42 - 70

|70|

x 100 = -28

70

x 100 = -40

Mark me brainliest if I helped:D

3 0
2 years ago
For the matrices below. Find all (real) eigenvalues. <br><br> A= [7 9]<br> [0 9]
Jet001 [13]

Answer:

The answer is "9 and 7".

Step-by-step explanation:

Given:

A=\left[\begin{array}{cc}7&9\\0&9\end{array}\right]

Using formula:

|A-\lambda \cdot I|= 0\\\\

\to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]-\lambda \left[\begin{array}{cc}1&0\\0&1\end{array}\right] |=0\\\\\\ \to |\left[\begin{array}{cc}7&9\\0&9\end{array}\right]- \left[\begin{array}{cc}\lambda&0\\0&\lambda\end{array}\right] |=0\\\\\\\to|\left[\begin{array}{cc}7-\lambda &9\\0&9-\lambda\end{array}\right]|=0\\\\\\\to|(7-\lambda)(9-\lambda)|=0\\\\\to (7-\lambda)(9-\lambda)=0\\\\\to 7-\lambda=0 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 9-\lambda=0\\\\

\to \lambda=7 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \lambda=9\\\\

8 0
3 years ago
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