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LenKa [72]
2 years ago
14

What is the area of this trapezoid?

Mathematics
2 answers:
timofeeve [1]2 years ago
8 0

Answer: 140 in^{2}

Step-by-step explanation:

The area for a trapeziod is A = \frac{1}{2}(b1+b2)h

We have almost everything we just need the total length of the top base, since it gives us the outer lengths we can find that by simply doing 4+6+15 which turns out to be 25

Now we can plug in our values:

A = \frac{1}{2}(25 + 15) x 7 = 140in^{2}

Daniel [21]2 years ago
7 0

Answer:

140 in2

Step-by-step explanation:

I did the test on 6th grade k12 !

(pls mark brainliest for my next rank)

hope this helped- vasuveda

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Please help!!!!!!!!!!!!!!!! Will mark brainliest! thanks!
madreJ [45]

gpm = 29.7 \times  {d}^{2}  \times  \sqrt{np}
this formula is used to determine gpm (gallons per minute) of flow with a known hose diameter (d) and nozzle pressure (np). The constant (29.7) is consistent when figuring flow with in gallons with a know pressure expressed in psi (pounds per square inch).

Scenario example: a firefighter is using a handline to fight fire with an 1 3/4 inch line with a nozzle pressure of 100 psi. How much water is the firefighter flowing when fighting fire?

gpm = 29.7 \times  {1.75}^{2}  \times  \sqrt{100}
3 0
3 years ago
8. If f(x) = 5x - 8, what is the value of f(3)?
Igoryamba

Answer: f(3) = 7

Step-by-step explanation:

f(3) = 5(3) - 8

15 - 8

f(3) = 7

7 0
2 years ago
Read 2 more answers
How do you factor something
Zepler [3.9K]
Finding what a number is diviseble by or finding multiples of a number
3 0
3 years ago
What are two different ways you can show 103?
valina [46]

Answer:

100+3, a hundred three.

Step-by-step explanation:

4 0
3 years ago
A swimming pool at a park measures 9.75 meters by 7.2 meters.
neonofarm [45]

Answer:

Part a) The area of the swimming pool is 70.2\ m^2

Part b) The total area of the swimming pool and the playground is 105.3\ m^2

Step-by-step explanation:

Part a) Find the area of the swimming pool

we know that

The area of the swimming pool is

A=LW

where

L is the length side

W is the width side

we have

L=9.75\ m\\W=7.2\ m

substitute the values

A=(9.75)(7.2)

A=70.2\ m^2

therefore

The area of the swimming pool is 70.2\ m^2

Part b) The area of the playground is one and a half times that of the swimming pool. Find the total area of the swimming pool and the playground

we know that

To obtain the area of the playground multiply the area of the swimming pool by one and a half

\frac{1}{2}(70.2)=35.1\ m^2

To obtain the total area of the swimming pool and the playground, adds the area of the swimming pool and the area of the playground

so

70.2\ m^2+35.1\ m^2=105.3\ m^2

therefore

The total area of the swimming pool and the playground is 105.3\ m^2

6 0
3 years ago
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