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sergiy2304 [10]
3 years ago
8

Factorize this expression completely using (a-b)² formula3a²- 36a + 108​

Mathematics
1 answer:
Novosadov [1.4K]3 years ago
6 0

Answer:

3a^2 - 36a + 108  = (\sqrt{3}a - 6\sqrt{3} )^2

Step-by-step explanation:

3a^2 = (\sqrt{3} a)^2\\108 = 9 \times 4 \times 3= 3^2 \times 2^2 \times 3 = (3\times2 \sqrt{3} )^2 = (6\sqrt{3})^2

so, a = \sqrt{3}  a \ , \ b = 6\sqrt{3} \\\\(a - b)^2 = a^2 -2ab + b^2\\\\-36a = -2ab\\\\-36a = -2 \times \sqrt{3} a \times 6\sqrt{3}

Therefore ,

3a^2 - 36a + 108 = (\sqrt{3}a )^2 - 2(\sqrt{3}a \times 6\sqrt{3} ) + (6\sqrt{3} )^2  = (\sqrt{3}a - 6\sqrt{3} )^2

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There was a 340,000 cattle placed on feed. Write an equivalent ration that could be used to find how many of these cattle were b
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An equivalent ratio would be 4/10, and the number of cattle would be 136,000.Explanation:The question asks for an equivalent ratio. This means a fraction that is equivalent to the fraction between 700-799, which is 2/5.To create an equivalent fraction, we multiply the numerator and denominator by the same number. Multiplying both by 2, we get (2*2)/(5*2) = 4/10.Tenths are useful when dealing with thousands, because taking a tenth involves getting rid of a zero. This means that 1/10 would be 34000; 4/10 would be 4 times that: 4(34000) = 136000.


Read more on Brainly.com - brainly.com/question/200236#readmore

7 0
3 years ago
What is the least common denominator of 4/5 and 1/10
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The least common denominator for the question you have supplied me with is 10. The least common multiple of the denominators, 5 and 10, is 10, making the LCD 10.
4 0
3 years ago
Read 2 more answers
PLEASE PLEASE HELP ME!!!
leonid [27]
I tried to show all work.

8 0
2 years ago
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PLEASE HELP ME I HAVING TROUBLE
viktelen [127]

Answer: f(-6) = -\frac{12}{11}, f(-4) = \frac{8}{9}, f(4) = -\frac{8}{9}, f(6) = \frac{12}{11}

<u>Step-by-step explanation:</u>

(-6, f(-6)) is an x,y coordinate.  They are asking what the y-value is when you plug in -6 for x.

f(x) = \frac{2x}{x^{2}-25}

f(-6) = \frac{2(-6)}{(-6)^{2}-25}

      = \frac{-12}{36-25}

      = -\frac{12}{11}

f(-4) = \frac{2(-4)}{(-4)^{2}-25}

      = \frac{-8}{16-25}

      = \frac{-8}{-9}

      = \frac{8}{9}

f(4) = \frac{2(4)}{(4)^{2}-25}

      = \frac{8}{16-25}

      = \frac{8}{-9}

      = -\frac{8}{9}

f(6) = \frac{2(6)}{(6)^{2}-25}

      = \frac{12}{36-25}

      = \frac{12}{11}

5 0
2 years ago
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