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FrozenT [24]
2 years ago
12

A bow of fruit is on the table. It contains 2 apples, five oranges, and four bananas. Nicholas and Timothy come home from school

and randomly grab one fruit each. What is the probability that they both grab oranges?
I already tried 5/11

Mathematics
2 answers:
ExtremeBDS [4]2 years ago
6 0

Answer:

I think the answer is 2/11.

klemol [59]2 years ago
4 0

Answer:

maybe 1/66

Step-by-step explanation:

??? sorry if im wrong

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Let the number of chocolate chips in a certain type of cookie have a Poisson distribution. We want the probability that a cookie
ludmilkaskok [199]

Answer:

\lambda \geq 6.63835

Step-by-step explanation:

The Poisson Distribution is "a discrete probability distribution that expresses the probability of a given number of events occurring in a fixed interval of time or space if these events occur with a known constant mean rate and independently of the time since the last event".

Let X the random variable that represent the number of chocolate chips in a certain type of cookie. We know that X \sim Poisson(\lambda)

The probability mass function for the random variable is given by:

f(x)=\frac{e^{-\lambda} \lambda^x}{x!} , x=0,1,2,3,4,...

And f(x)=0 for other case.

For this distribution the expected value is the same parameter \lambda

E(X)=\mu =\lambda

On this case we are interested on the probability of having at least two chocolate chips, and using the complement rule we have this:

P(X\geq 2)=1-P(X

Using the pmf we can find the individual probabilities like this:

P(X=0)=\frac{e^{-\lambda} \lambda^0}{0!}=e^{-\lambda}

P(X=1)=\frac{e^{-\lambda} \lambda^1}{1!}=\lambda e^{-\lambda}

And replacing we have this:

P(X\geq 2)=1-[P(X=0)+P(X=1)]=1-[e^{-\lambda} +\lambda e^{-\lambda}[]

P(X\geq 2)=1-e^{-\lambda}(1+\lambda)

And we want this probability that at least of 99%, so we can set upt the following inequality:

P(X\geq 2)=1-e^{-\lambda}(1+\lambda)\geq 0.99

And now we can solve for \lambda

0.01 \geq e^{-\lambda}(1+\lambda)

Applying natural log on both sides we have:

ln(0.01) \geq ln(e^{-\lambda}+ln(1+\lambda)

ln(0.01) \geq -\lambda+ln(1+\lambda)

\lambda-ln(1+\lambda)+ln(0.01) \geq 0

Thats a no linear equation but if we use a numerical method like the Newthon raphson Method or the Jacobi method we find a good point of estimate for the solution.

Using the Newthon Raphson method, we apply this formula:

x_{n+1}=x_n -\frac{f(x_n)}{f'(x_n)}

Where :

f(x_n)=\lambda -ln(1+\lambda)+ln(0.01)

f'(x_n)=1-\frac{1}{1+\lambda}

Iterating as shown on the figure attached we find a final solution given by:

\lambda \geq 6.63835

4 0
2 years ago
Please solve fast, easy question
DochEvi [55]

Answer:

I think its C

Step-by-step explanation:

Hope this Helps :)

Plz mark Brainliest If Correct!!

6 0
2 years ago
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Which is a prime number 21 23 25 27 29
UNO [17]

Answer:

29 :)

it is 29 because 29 falls under all the prime number characteristics

8 0
2 years ago
A pair of parallel lines is cut by a transversal:
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3 0
2 years ago
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1. Solve x/5-3&lt;5<br><br> A. x&lt;2/5<br> B. x&lt;10<br> C. x&lt;40
blsea [12.9K]

x/5-3<5

add 3 to each side

x/5 < 8

multiply each side by 5

x<40

Choice C


5 0
3 years ago
Read 2 more answers
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