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Mkey [24]
2 years ago
8

Simplify. (-2w2+5w-4) + (3w? +7w+6) Answer ASAP Will give brainlest

Mathematics
1 answer:
scoray [572]2 years ago
6 0

Answer:

w² + 12w + 2

Step-by-step explanation:

( - 2w² + 5w - 4 ) + ( 3w² + 7w + 6 )

= 3w² - 2w² + 5w + 7w + 6 - 4

= 1w² + 12w + 2

= w² + 12w + 2

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What numbers multiply to -30 and add to -3
krek1111 [17]
Let the numbers be x and y.  Then xy = -30 and  x+y = -3.

Solve xy = -30 for y:    y = -30/x

subst. -30/x for y in   x+y= -3:     x  -  30/x = -3

Multiply all 3 terms by x:  x^2 - 30 = -3x, so   x^2 + 3x - 10 = 0

Solve this quadratic equation for x.     x: {-5, 2}

If x = -5, then   x+y = -3 becomes -5 + y = -3, and y = 2.

You should check to determine whether x=2 is also correct.  If it is, what is the corresponding y value?
3 0
3 years ago
WILL GIVE BRAINLIEST! NEED FAST!
dybincka [34]

Answer:

650=65% of 1000

Step-by-step explanation:

650-600=65 or 65%

3 0
3 years ago
How do I multiply mixed numbers? For example: 6 4/5 x 8 9/10. I need help I have a quiz on this.​
nordsb [41]

Step-by-step explanation:

First you have to convert each number to improper fractions.

Next you have to multiply denominator to denominator, and fraction to fraction.

Then simplify your final answer to the lowest form possible.

Hope this helps :)

6 0
2 years ago
4. Diego is thinking of two positive numbers. He says, "If we triple the first number and
aleksandr82 [10.1K]

Answer:

3<em>x </em>+ 2<em>y</em> = 34. and two possible pairs of positive numbers are  (<em>x</em>, <em>y</em>) = (10, 2) and (<em>x</em>, <em>y</em>) = (4, 11).

Step-by-step explanation:

 Let the First positive number be <em>x</em> and second positive number be <em>y.</em>

Triple of first number = 3<em>x</em>

double of second number = 2<em>y</em>

According to question,

3<em>x </em>+ 2<em>y</em> = 34

Therefore, the equation is 3<em>x </em>+ 2<em>y</em> = 34

So the two possible pair of numbers Diego would be thinking of must satisfy the equation 3<em>x </em>+ 2<em>y</em> = 34

Now,  3<em>x </em>+ 2<em>y</em> = 34

3<em>x </em>= 34 - 2<em>y</em>

Let x = 10 and by substituting its value in above expression,

3 \times 10 = 34 - 2y

30 = 34 - 2y

2y = 34 - 30

2y = 4

y = 2

Therefore first pair (<em>x</em>, <em>y</em>) = (10, 2)

In the same way put x = 4 then,

3<em>x </em>= 34 - 2<em>y</em>

3 \times 4 = 34 - 2y

2y = 34 - 12

2y = 22

y = 11

Therefore first pair (<em>x</em>, <em>y</em>) = (4, 11)

Therefore, (<em>x</em>, <em>y</em>) = (4, 11) and  (<em>x</em>, <em>y</em>) = (10, 2) are the two possible pairs of numbers Diego could be thinking of as these both values satisfy the equation 3<em>x </em>+ 2<em>y</em> = 34.  

8 0
3 years ago
I really need this answer
HACTEHA [7]

Answer:

A is the answer.

Step-by-step explanation:

What you do is you multiply -6 into each of the fractions and then add or minus the fractions together.

-6(1/4x)=-3/2x

-6(-2/3x)=4x

-6(5/6x)=-5x

-3/4x+4x-5x=-2.5 or A.

4 0
3 years ago
Read 2 more answers
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