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Trava [24]
3 years ago
10

X - 21 = 43 - 4x Help me please

Mathematics
2 answers:
kramer3 years ago
7 0

Answer:

x= 64/5

Step-by-step explanation:

x+4x-21=43-4x+4x

5x-21=43

5x-21+21=43+21

5x= 64

5/5x=64/5

x= 64/5

lukranit [14]3 years ago
3 0

Answer:

x=12.8

Step-by-step explanation:

x-21=43-4x

5x-21=43

5x=64

x=12.8

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If 4^2x+1 = 4, then =
Aneli [31]

Step-by-step explanation:

step 1. what is the question? probably solve for x. okay.

step 2. 4^(2x) + 1 = 4

step 3. 4^(2x) = 3 subtract 1 from each side

step 4. ln4^(2x) = ln3 take on of each side

step 5. 2xln4 = ln3 definition of logs

step 6. 2x = ln3/ln4 divide both sides by ln4

step 7. x = ln3/2ln2^2 divide both side by 2 and replace 4 with 2^2

step 8. x = ln3/4ln2.

4 0
3 years ago
What are the domain and range of f(x) = 2|x -4|? <br> plz i'm in need
mafiozo [28]

Answer:

Domain: (-∞, ∞)

Range: [0, ∞)

Step-by-step explanation:

The domain represents what x can be. In this scenario, we do not have x as a denominator, and there is nothing limiting x, so its domain is (-∞, ∞)

The range represents what f(x) can be, Because |x-4| is in absolute value, the lowest |x-4| can be is 0, and as a result, the lowest value of 2|x-4| is 2*0=0. The maximum value of f(x) is ∞ as an absolute value does not limit the maximum, making the range [0, ∞)

6 0
3 years ago
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jolli1 [7]

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2 years ago
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6 0
3 years ago
Find the value of x
fgiga [73]

\qquad \qquad  \bf \huge\star \:  \:  \large{  \underline{Answer} }  \huge \:  \: \star

  • x = 35°

\textsf{  \underline{\underline{Steps to solve the problem} }:}

\qquad❖ \:  \sf \:4x + 1 + x + 4 = 180

[ by linear pair ]

\qquad❖ \:  \sf \:5x + 5 = 180

\qquad❖ \:  \sf \:5(x + 1) = 180

\qquad❖ \:  \sf \:x + 1 = 180 \div 5

\qquad❖ \:  \sf \:x + 1 = 36

\qquad❖ \:  \sf \:x = 36 - 1

\qquad❖ \:  \sf \:x = 35

\qquad \large \sf {Conclusion}  :

  • x = 35°
7 0
2 years ago
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