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ankoles [38]
3 years ago
15

Which of the following expressions could be used to represent "the difference between -12 and 10"?

Mathematics
2 answers:
slava [35]3 years ago
7 0

Answer:

-12-10

Step-by-step explanation:

difference means subtraction so it is saying subtract -12 and 10

pshichka [43]3 years ago
3 0

Answer:

-2

Step-by-step explanation:

I took the test :)

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3. Problem 2: Suppose a radio manufacturer has the total cost function C (x) = 43x + $ 1850 and the revenue function R (x) = $ 8
OLEGan [10]

Given that,

Total cost function, C (x) = 43x + $1850

The revenue function R (x) = $80x

To find,

The number of units that must be produced and sold to break even.

Solution,

At break even, cost = revenue

43x + $1850 = $80x

Subtract 80x from both sides.

43x + 1850 -80x = $80x -80x

1850 = 80x-43x

37x = 1850

x = 50

So, the required number of units are 50.

8 0
3 years ago
How do I solve for x? (the picture has the problem)
max2010maxim [7]

Answer:

x = 21.013155617496

Step-by-step explanation:

we have a right triangle then ,

\cos \left( 36\right)  =\frac{17}{x}

Then

x=\frac{17}{\cos \left( 36\right)  } = 21.013155617496

Then

x ≈ 21

5 0
2 years ago
Read 2 more answers
F(x)= 2x^3- x^2 +x+ 1 is divided by 2x +1.
ololo11 [35]

Answer:

Step-by-step explanation:

               x^2

           --------------------------------------------------

2x + 1  /  2x^3     -     x^2    +      x      +    1

               2x^3    +    x^2

              -----------------------

                                    0 + x + 1

                                        x + 1

The quotient is  x^2 + ------------

                                       2x + 1

8 0
2 years ago
It's a question from real and complex numbers which I can't solve. so someone PLZ HeLp​
Semmy [17]

Answer:

\frac{1}{5}

Step-by-step explanation:

Using the rules of exponents

a^{m} × a^{n} = a^{(m+n)}, \frac{a^{m} }{a^{n} } = a^{(m-n)}, (a^m)^{n} = a^{mn}

Simplifying the product of the first 2 terms

\frac{a^{p^2+pq} }{a^{pq+q^2} } × \frac{a^{q^2+qr} }{a^{qr+r^2} }

= a^{p^2-q^2} × a^{q^2-r^2}

= a^{p^2-r^2}

Simplifying the third term

5((a^p+r)^{p-r}

= 5a^{(p+r)(p-r)} = 5a^{(p^2-r^2)}

Performing the division, that is

\frac{a^{(p^2-r^2)} }{5a^{(p^2-r^2)} } ← cancel a^{(p^2-r^2)} on numerator/ denominator leaves

= \frac{1}{5}

4 0
3 years ago
Suppose y varies inversely as x, and y=25 when x=3. Find x when y=15
malfutka [58]

Answer:

If

y

varies inversely as

x

then

XXX

x

⋅

y

=

c

for some constant

c

We are told when

x

=

2

then

y

=

15

So

XXX

2

⋅

15

=

c

XXX

⇒

c

=

30

and

XXX

x

⋅

y

=

30

Therefore when

y

=

3

XXX

x

⋅

3

=

30

XXX

→

x

=

10

Step-by-step explanation:

3 0
3 years ago
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