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Sav [38]
3 years ago
10

If (44)x = 432, what is the value of x? 04 07 O 8 O 28

Mathematics
1 answer:
sdas [7]3 years ago
4 0

Answer: x = 9.8181......

Step-by-step explanation:

(44)x =432

Take out Parentheses:

44x = 432

Divide both sides by 44:

x =  9.8181......

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(will give brainliest) find the value of x
Sedaia [141]

Answer:

x = 180 - [(180 - 3x) + (180 - 2x)]

Step-by-step explanation:

Start off by finding the angles of the triangle

Angle F = 180 - 3x

The angle across from I (which I will call I) = 180 - 2x

Angle G = 180 - (F + I)

Now that we know what G is, we know what x is because the Alternate Exterior Angles Theorem states that if a pair of parallel lines are cut by a transversal, then the alternate exterior angles are congruent. So pretty much X = G

Therefore x =  180 - (F + I) or otherwise said as:

x = 180 - [(180 - 3x) + (180 - 2x)]

I hope this is helpful :)

5 0
3 years ago
Read 2 more answers
A random draw is being designed for 210 participants. A single winner is to be chosen, and all the participants must have an equ
Over [174]

Answer: The correct number of balls is (b) 4.

Step-by-step explanation:  Given that a single winner is to be chosen in a random draw designed for 210 participants. Also, there is an equal probability of winning for each participant.

We are using 10 balls, numbered through 0 to 9. We are to find the number of balls which needs to be picked up, regardless of order, so that each of the 210 participants can be assigned a unique set of numbers.

Let 'r' represents the number of balls to be picked up.

Since we are choosing from 10 balls, so we must have

^{10}C_r=210.

The value of 'r' can be any one of 0, 1, 2, . . , 10.

Now,

if r = 1, then

^{10}C_1=\dfrac{10!}{1!(10-1)!}=\dfrac{10!}{1!9!}=\dfrac{10\times 9!}{1\times 9!}=10

If r = 2, then

^{10}C_2=\dfrac{10!}{2!(10-2)!}=\dfrac{10!}{2!8!}=\dfrac{10\times 9\times 8!}{2\times 1\times 8!}=45

If r = 3, then

^{10}C_3=\dfrac{10!}{3!(10-3)!}=\dfrac{10!}{3!7!}=\dfrac{10\times 9\times 8\times 7!}{3\times 2\times 1\times 7!}=120

If r = 4, then

^{10}C_4=\dfrac{10!}{4!(10-4)!}=\dfrac{10!}{4!6!}=\dfrac{10\times 9\times 8\times\times 7\times 6!}{4\times 3\times 2\times 1\times 6!}=210.

Therefore, we need to pick 4 balls so that each participant can be assigned a unique set of numbers.

Thus, (b) is the correct option.

4 0
3 years ago
Read 2 more answers
FRQ 1
Reptile [31]

Answer:

a) The number of visits between the patrons who buys the season passes shows higher frequency than those who did not buy season passes, in general. However, the minimum value of 1 visit is present for both cases.

b) The mean visits of the patrons are just PARAMETERS. If you want to test your hypothesis using hypothesis testing, the statistics are the z or t scores comparing the parameters (means).

c) The proportion who would have paid less are those with 2 or fewer visits because they would only just paid $82 instead of $100.

Number of patrons with 2 or fewer visits: 16

Total number of patrons who bought season passes: 30

Proportion who would've paid less = 16/30 = 0.5333

Step-by-step explanation:

I just did it

5 0
3 years ago
Simplify the expression |ab^3| , if: a 0
Nutka1998 [239]

Answer:[45] i think

Step-by-step explanation:

5 0
3 years ago
Can someone solve this for me please?
Ksivusya [100]
The y-in is -6
The x- in is -1 and -6
The vertex is (-3.5,-6.25)
The axis is -3.5
5 0
3 years ago
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