So we have lengths a and b and are given:
2a+2b = 66 => a+b = 33 => a= 33-b
a*b = 272
plug in one into the other:
(33-b)b = 272 => -b^2 +33b - 272 = 0
Can be factored as (b-16)(b-17) = 0, if you don't "see" this immediately, use the well known abc formula to find b.
So a=16 and b=17 or vice versa.
39=9x+7-3x+20
Subtract 27 from each side
12=6x
2=x
Now plug in 2 for x to find AB and BC
9x+7= AB
9(2)+7=AB
18+7= AB
25= AB
-3x+20= BC
-3(2)+20= BC
-6+20= BC
14= BC
I believe 62 because it it’s closer to an hour
Divide 3 on the numerator and denominator.
Hoped this helped.
~Bob Ross®
