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olasank [31]
3 years ago
14

Monet measures the diameter of an Oreo and finds that each cookie is 1.75 inches across. Using Monet's measurement, calculate th

e circumference of an Oreo. Use 3.14 as an estimation for π.
Mathematics
1 answer:
Anon25 [30]3 years ago
3 0

Answer:

5.495 inches.

Step-by-step explanation:

We have been given that Monet measures the diameter of an Oreo and finds that each cookie is 1.75 inches across. We are asked to find the circumference of an Oreo.

We know that circumference of circle is equal to 2\pi r, where r represents radius of circle.

We also know that diameter is 2 times radius.

D=2r

Upon substituting 2r=\text{ 1.75 in}, we will get:

\text{The circumference of an Oreo}=\text{ 1.75 in}\times \pi

Using 3.14 as an estimation for π, we will get:

\text{The circumference of an Oreo}=\text{ 1.75 in}\times 3.14

\text{The circumference of an Oreo}=5.495\text{ in}

Therefore, the circumference of an Oreo would be 5.495 inches.

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Answer:

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Step-by-step explanation:

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What is the volume of a cone that has a height of 7 mm and a radius of 3 mm?
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Find the sum of the first 20 terms of the arithmetic sequence 4, -4, -12, -20​
Vsevolod [243]

Answer:

The sum of the first 20 terms is -1440.

Step-by-step explanation:

We want to find the sum of the first 20 terms of the arithmetic sequence:

4, -4, -12, -20...

The sum of an arithmetic sequence is given by:

\displaystyle S=\frac{k}{2}(a+x_k)

Where <em>k</em> is the number of terms, <em>a</em> is the initial term, and <em>x</em>_<em>k</em> is the last term.

Since we want to find the sum of the first 20 terms, <em>k</em> = 20.

Our initial term <em>a</em> is 4.

Our last term is also the 20th term as we want the sum of the first 20 terms.

To find the 20th term, we can write an explicit formula for our sequence. The explicit formula for an arithmetic sequence is given by:

x_n=a+d(n-1)

Where <em>a</em> is the initial term, <em>d</em> is the common difference, and <em>n</em> is the <em>n</em>th term.

Our initial term is 4. From the sequence, we can see that our common difference is -8 since each subsequent term is eight less than the previous term. Therefore:

x_n=4-8(n-1)

Then the last or 20th term is:

x_{20}=4-8(20-1)=4-8(19)=-148

Therefore, the sum of the first 20 terms are:

\displaystyle\begin{aligned} S_{20}&=\frac{(20)}{2}\left((4)+(-148))\\&=10(-144) \\&= -1440\end{aligned}

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