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Svetradugi [14.3K]
3 years ago
12

In trip 1 you drove 104 miles in 4 gallons; in trip 2 you drove 78 miles how many gallons did you use in trip 2

Mathematics
2 answers:
bearhunter [10]3 years ago
6 0
3. The answer is 3 gallons
BlackZzzverrR [31]3 years ago
4 0
First do 104/4 which equals which equals 26
so you can drive 26miles on one gallon

then do 78/26 which equals 3

so you used 3 gallons of gas on trip 2
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Can someone help me with this please
erastova [34]

Not positively sure but I believe it goes like this

Answer: 9x+26+5x=180

14x+26=180

180-26=14x

14x=154

X=15

8 0
2 years ago
Please help me with this problem
diamong [38]
20%

(300-250)/250=0.2
8 0
3 years ago
Solve the following system of equations using the substitution method.
BartSMP [9]

Answer:

B

Step-by-step explanation:

First label the equations.

6x +3y= 18 -----(1)

y= -2x +5 -----(2)

subst. (2) into (1):

6x +3(-2x +5)= 18

6x +3(-2x) +3(5)= 18 (expand)

6x -6x +15= 18

15= 18 (simplify)

(reject)

There is no solution.

<u>Further explanation</u><u>:</u>

If I rewrite the first equation into the form of y=mx+c, I would get

6x +3y=18

3y= 18 -6x (bring y term to one side)

y= 6- 2x (÷3 throughout)

y= -2x +6

Notice that the gradients of both lines are equal ( -2). This implies that they are parallel to each other and will never meet. Hence there are no solutions.

3 0
2 years ago
Name all similar triangles to triangle CDE.
blondinia [14]

Answer:ceo

Step-by-step explanation:

Ceo

4 0
3 years ago
In how many ways can five children posing for a photograph line up in a row?
Shtirlitz [24]

Answer:

number of ways = 120

Step-by-step explanation:

The number of ways five children can pose for a photograph line up in a row is given by the number of permutations of 5 elements in 5 different positions (positions in the line), then

number of ways = number of permutations of 5 elements = 5! = 5 * 4 * 3 * 2 * 1 = 120

Since the first children that occupies the line can be on any of the positions (5 positions) , but then the second one can choose any of the 4 remaining positions (since the first children had already occupied one) , the third can choose 3 ... and so on.

5 0
3 years ago
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