Answer: 16 square units
Step-by-step explanation:
let the vertex in quadrant I be (x,y)
then the vertex in quadratnt II is (-x,y)
base of the rectangle = 2x
height of the rectangle = y
Area = xy
= x(12 - x²)
= -x³ + 12x
d(area)/dx = 3x² - 12 = 0 for a maximum of area
3x² = 12
x² = 4
x = ±2
y = 12-4 = 8
So, the largest area = 2 x 8 = 16 square units
It is 5 1/9 after being simplified
Answer:
B y = -1/2x + 7/2
Step-by-step explanation:
We know that it has a negative slope since the points go from the top left to the bottom right
We can eliminate A and D
The y intercept is where it crosses the y axis
It should cross somewhere between 2 and 4
C has a y intercept of 9 which is too big
Lets verify with a point
x = -4
y = -4(-4)+9 = 16+9 = 25 (-4,25) not even close to being near the points on the graph
checking B
y = -1/2 (-4) +7/2
= 2 + 7/2 = 11/2 = 5.5 it seems reasonable
