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arsen [322]
2 years ago
14

Please help 7 grade math asap!!!!!!! only worry about 11

Mathematics
1 answer:
chubhunter [2.5K]2 years ago
4 0
-1.3 is farther from 0 because -1.3 is less than negative one, where as 4 fifths is more than negative one. -1.3 is farther.
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Graph the line x = -3
-BARSIC- [3]

Answer:

Draw a vertical line passing through (-3,0)

5 0
3 years ago
​Recently, a random sample of 13-18 year olds was​ asked, "How much do you currently have in​ savings?" The data in the table re
Sonbull [250]

Answer:

μ = 235.38

σ = 234.54

Step-by-step explanation:

Assuming the table is as follows:

\left[\begin{array}{cc}Savings&Frequency\\\$0-\$199&339\\\$200-\$399&86\\\$400-\$599&55\\\$600-\$799&18\\\$800-\$999&11\\\$1000-\$1199&8\\\$1200-\$1399&3\end{array}\right]

This is an example of grouped data, where a range of values is given rather than a single data point.  First, find the total frequency.

n = 339 + 86 + 55 + 18 + 11 + 8 + 3

n = 520

The mean is the expected value using the midpoints of each range.

μ = (339×100 + 86×300 + 55×500 + 18×700 + 11×900 + 8×1100 + 3×1300) / 520

μ = 122400 / 520

μ = 235.38

The variance is:

σ² = [(339×100² + 86×300² + 55×500² + 18×700² + 11×900² + 8×1100² + 3×1300²) − (520×235.38²)] / (520 − 1)

σ² = 55009.7

The standard deviation is:

σ = 234.54

6 0
3 years ago
2
Zigmanuir [339]

Answer:

The weight of the water in the pool is approximately 60,000 lb·f

Step-by-step explanation:

The details of the swimming pool are;

The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet

The depth of the pool = 5 feet

The density of the water  in the pool = 60 pounds per cubic foot

From the question, we have;

The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g

The volume of water in the pool = Cross-sectional area × Depth

∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³

Acceleration due to gravity, g ≈ 32.09 ft./s²

∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N

266,196.089 N ≈ 60,000 lb·f

The weight of the water in the pool ≈ 60,000 lb·f

6 0
2 years ago
Is AJKL = AMNO? If so, name the congruence postulate that applies.
romanna [79]
Answer:A that is what I think the answer is
6 0
2 years ago
Write on equation if the slope is 3/4<br> and the y-intercept is -4,
KonstantinChe [14]

Answer:

thw abswer os tywentr yaxel

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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