Answer:
0.43×10²³ atoms
Explanation:
Given data:
Mass of LiBrO₂ = 4.28 g
Number of atoms of oxygen = ?
Solution:
Number of moles = mass/molar mass
Number of moles = 4.28 g/ 118.84 g/mol
Number of moles = 0.036 mol
We can see 1 mole of LiBrO₂ contain 2 mole of oxygen atm.
0.036 mol × 2 = 0.072 mol
1 mole contain 6.022×10²³ atoms
0.072 mol × 6.022×10²³ atoms / 1mol
0.43×10²³ atoms
The electron dot diagram for the oxygen atom shows six electrons around the symbol of the atom.
<h3>What is the electron dot diagram?</h3>
The electron dot diagram is the diagram of atoms of elements showing only the valence electrons present in the atom represented with dots.
The electron dot diagram for the oxygen atom is drawn as follows:
- The number of valence electrons in oxygen atom is determined; valence electrons = 6
- The symbol for the oxygen atom is written
- The valence electrons are shown as dots around the symbol of the element.
In conclusion, the electron dot diagram uses dots around the symbol of an atom to show the valence electrons in the atom.
Learn more about electron dot diagram at: brainly.com/question/5835591
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The statements which correctly describe the Cl-Cl bond is:
It is a sigma bond.
It is formed by overlap of two hybrid orbitals.
Explanation:
The 2 atoms of the chlorine atom are bonded by single bond by sharing of electrons as chlorine has 7 electrons in its outer shell.
1s22s2p63s23p5 configuration of each atom
A covalent bond is formed between the two chlorine atoms.
The electrons are shared by molecular orbitals by overlapping the orbital as each of the chlorine atom will try to complete its octet. The electrons from p orbitals are shared hence sigma bond.
There is no hybridization in Cl2 it only has only overlapping of electrons in p orbitals.