Question

Where are the minimum and maximum values for f(x)=−2+4cosx on the interval [0,2π]?

Answer 1

Answer:

$f(x) = - 2 + 4 \cos(x) \\ for \: minimum \: \: x = 0 \\ f(0) = - 2 + 4 \cos(0) \\ minimum \: value = 2 \\ for \: maximum \: value \: \: x = 2\pi \\ f(2\pi) = - 2 + 4 \cos(2\pi) \\ maximum \: value = - 2$