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Vedmedyk [2.9K]
3 years ago
14

Judy Ring purchased a watch with a retail price of $8,000. She still has to pay a sales tax of 6% and an excise tax of 10%. Sinc

e the jeweler is shipping the watch, there's an additional $20 shipping charge. The total purchase price of this watch for Judy i
Mathematics
2 answers:
Advocard [28]3 years ago
8 0

Answer: Total purchase price of this watch is $9300.

Step-by-step explanation:

Since we have given that

Retail price of watch = $8000

Rate of sales tax = 6%

Amount of sales tax becomes

\dfrac{6}{100}\times 8000\\\\=\$480

Rate of excise tax = 10%

Amount of excise tax is given by

\dfrac{10}{100}\times 8000\\\\=\$800

So, Amount of watch after sales tax becomes

\$8000+\$480+\$800\\\\=$9280

Amount of additional shipping charge = $20

Amount of watch after additional shipping charge becomes

\$9280+20\\\\=\$9300

Hence, Total purchase price of this watch is $9300.

Bumek [7]3 years ago
7 0
The total purchase price of the watch is: $9,300

$8,000 + (0.06 × $8,000) + (0.10 × 8,000) + $20

$8,000 + $480 + $800 + $20

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Answer:

The total cost is $81.78

Step-by-step explanation:

First lets calculate the tip

tip = cost * percent of tip

tip = 65.42*.25

tip = 16.355

Which rounds to 16.36  since we are working with money and round to the nearest cent

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                     =81.78

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3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
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For what values of $x$ is $$\frac{x^2 + x + 3}{2x^2 + x - 6} \ge 0?$$ note: be thorough and explain why all points in your answe
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To solve the inequality \frac{x^2+x+3}{2x^2+x-6}\ge \:0

\mathrm{Factor\:the\:left\:hand\:side\:}\frac{x^2+x+3}{2x^2+x-6}:

The numerator x^2+x+3 is not factorizable.

so factor the denominator 2x^2+x-6:

2x^2+x-6=\left(2x^2-3x\right)+\left(4x-6\right)=x\left(2x-3\right)+2\left(2x-3\right)\\ \mathrm{Factor\:out\:}x\mathrm{\:from\:}2x^2-3x\mathrm{:\quad }x\left(2x-3\right)\\ \mathrm{Factor\:out\:}2\mathrm{\:from\:}4x-6\mathrm{:\quad }2\left(2x-3\right)\\

Now take \mathrm{Factor\:out\:common\:term\:}\left(2x-3\right)

Then we get factor of the denominator as \left(2x-3\right)\left(x+2\right)

Thus \frac{x^2+x+3}{2x^2+x-6}=\frac{x^2+x+3}{\left(x+2\right)\left(2x-3\right)}

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Signs of x^2+x+3>0

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x\frac{3}{2} is the required solution of the given inequality.

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3 years ago
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