Answer:
Cubic polynomial has zeros at x=−1x=−1 and 22, is tangent to x−x−axis at x=−1x=−1, and passes through the point (0,−6)(0,−6).
So cubic polynomial has double zero at x=−1x=−1, and single zero at x=2x=2
f(x)=a(x+1)2(x−2)f(x)=a(x+1)2(x−2)
f(0)=−6f(0)=−6
a(1)(−2)=−6a(1)(−2)=−6
a=3a=3
f(x)=3(x+1)2(x−2)f(x)=3(x+1)2(x−2)
f(x)=3x3−9x−6
Answer:
-44
Step-by-step explanation:
If the input is -28, that means x = -28, so we plug -28 in for x and solve for y, which is the output:
y = x - 16
y = -28 - 16 = -44
The answer is thus -44.
9514 1404 393
Answer:
-4 1/8
Step-by-step explanation:
Many people find it easier to factor out -1, then do the addition. The fractions need a common denominator before they can be added. A suitable denominator that is a multiple of both 4 and 8 is 8.
The fraction 1/4 = (1/4)(2/2) = (1·2)/(4·2) = 2/8.
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So, the problem can be rewritten as ...
-(1 7/8 +2 2/8)
= -((1+2) +(7/8 +2/8))
= -(3 +9/8)
The fraction 9/8 is an improper fraction equal to 8/8 +1/8 = 1 1/8. Then the sum is ...
-(3 +1 1/8) = -4 1/8
Answer:
11/6 or decimal 1.8333... + 4.9 = 6.733333....
Step-by-step explanation:
Simplify the following:
(3 + 2/3)/2
Express 4/6 in its lowest form by cancelling out gcd(4, 6) = 2 from the numerator and denominator. 4/6 = (2×2)/(2×3) = 2/3:
(2/3 + 3)/2
Put 3 + 2/3 over the common denominator 3. 3 + 2/3 = (3×3)/3 + 2/3:
((3×3)/3 + 2/3)/2
3×3 = 9:
(9/3 + 2/3)/2
9/3 + 2/3 = (9 + 2)/3:
((9 + 2)/3)/2
9 + 2 = 11:
(11/3)/2
11/3×1/2 = 11/(3×2):
11/(3×2)
3×2 = 6:
Answer: 11/6 or decimal 1.8333... + 4.9 = 6.733333....
