Answer:
The area of the park is calculated through the equation,
A = 0.5ab(cos C)
Substituting the given above,
A = 0.5(533 ft)(525 ft)(cos 53°)
A = 84201.44 ft²
2. We find the radius of the second figure by the equation,
r = C / 2π
Substituting,
r = (30 in) / (2π) = 4.77 in
The radius of the first one is 9 inches. Getting the difference of these two figures will give us an answer of 4.225 inches.
Thanks Useless
ansverwinterblanco
Diameter of the basketball rim = 18 inches
Circumference of the basketball = 30 inches
You would have to fin the area so= pi*r^2
Basketball rim = 3.14 * (18/2)^2 = 3.14 * 9^2 = 3.14 * 81 = 254.34 in^2
The find the Circumference so= 2*pi*r
30 = 2*3.14*r
r = 30 / (2*3.14) = 30 / 6.28 = 4.78 inches
basketball = 3.14 * (4.78)^2 = 3.14 * 22.85 = 71.75 in^2
254.34 - 71.75 = 182.59 in^
On a coin there is 2 sides so there is an even chance so if it’s 50 / 50 you would have to do more than 100 tosses to get over 60 heads
Answer : 13502 ft
Circumference of crater 2 pi r
Diameter = 4300
Radius = (4300/2)
Distance = 2 × 3.14 × (4300/2)
= 13502 ft
Hope it helped!
What grade you in and what unit lesson is this, I might be able to help you. I go to the same school.
