Help pls<br> What is the solution to this system of equations?<br> x = 12 − y<br> 2x + 3y = 29

You need to paint a decorative garden ornament that is in the shape of pyramid with a square base

KATRIN_1 [288]

Step-by-step explanation:

Total Surface area of a pyramid is given as

= Lateral surface area + area of base.

Lateral surface area = 1/2×perimeter of base×slant height

given the base is square with side 9 in , and slant height of 12 inches.

therefore, LSA = 1/2(9*4)×12 = 216 in^2

Now, TSA = LSA + Base area = 216+9^2 = 297 in^2

a) It is given that the pyramid is smaller therefore, it will require lesser paint than the original pyramid ( The TSA of the smaller pyramid cannot be calculated as its dimentions are not given).

b) It can not be solved as dimensions are missing in the question.

However, the logic has been explained in the soluion one easily put values to find the solution.

7 0

3 years ago

The diagram shows a circle of radius 1 contained in a square. If the area of the circle equals x% of the area of the square, the

11111nata11111 [884]

Answer:

Area of square with a side of 2r = 2(1) = 2 = 2^2 = 4

Area of circle = pi ( 1)^2 = pi

x = pi / 4 ≈ .79 = 79%

7 0

2 years ago

When Alice spends the day with the babysitter, there is a 0.6 probability that she turns on the TV and watches a show. Her littl

slava [35]

Answer:

a) There is a 48% probability that both Alice and Betty watch TV tomorrow.

b) There is a 48% probability that Betty watches TV tomorrow.

c) There is a 12% probability that only Alice watches TV tomorrow.

Step-by-step explanation:

We have these following probabilities:

A 60% probability that Alice watches TV.

If Alice watches TV, an 80% probability Betty watches TV.

If Alice does not watch TV, a 0% probability that Betty watches TV, since she cannot turn the TV on by herself.

a) What is the probability that both Alice and Betty watch TV tomorrow?

Alice watches 60% of the time. Betty watches in 80% of the time Alice watches. So:

$P = 0.6*0.8 = 0.48$

There is a 48% probability that both Alice and Betty watch TV tomorrow.

b) What is the probability that Betty watches TV tomorrow?

Since Betty only watches when Alice watches(80% of the time), this probability is the same as the probability of both of them watching. So

$P = 0.6*0.8 = 0.48$

There is a 48% probability that Betty watches TV tomorrow.

c) What is the probability that only Alice watches TV tomorrow?

There is a 60% probability that Alice watches TV tomorrow. If she watches, there is an 80% probability that Betty watches and a 20% probability she does not watch.

So

$P = 0.6*0.2 = 0.12$