All categories

2 years ago

Peter is asked to guess a number and here is the clue: it is 25% of 60% of 500.

Mathematics

1 answer:

sweet [91]2 years ago

8 0

Answer:

OK I think you have to do it like that:

500 is 100%. You have to calculate 500 through 60% and the result through 25%.

You might be interested in

The ________________ measures the spread of the middle 50% of the data set.

Scilla [17]

Answer:

C. interquartile range

Step-by-step explanation:

using this to show im right

"The interquartile range (IQR) is the difference between the upper (Q3) and lower (Q1) quartiles, and describes the middle 50% of values when ordered from lowest to highest."

Hope This Helped

6 0

1 year ago

Textbooks are exempted from PST in Ontario. If the total cost of a book

Andrei [34K]

Answer:

4.24

Step-by-step explanation:

Total price = price of the book + 5% of the price of the book

T = total price P = price of the book G = GST

T = P + G

and

G = 5% of P = 0.05P

therefore

T = P + 5%P = 1P + 0,05P = 1.05P

P = T/1.05 = 89/1.05 ≅ 84.76 (it is 84.7619047619)

G = 89 - 84.76 = 4.24

8 0

3 years ago

The wholesale price for a desk is $199. A certain furniture store marks up the wholesale price by 24%. Find the price of the des

eduard

Answer:

246.76$

Step-by-step explanation:

199 x .24 =

47.76

199 + 47.76 =

246.76

5 0

2 years ago

Suppose a tank contains 400 gallons of salt water. If pure water flows into the tank at the rate of 7 gallons per minute and the

Strike441 [17]

Answer:

Step-by-step explanation:

This is a differential equation problem most easily solved with an exponential decay equation of the form

$y=Ce^{kt}$ . We know that the initial amount of salt in the tank is 28 pounds, so

C = 28. Now we just need to find k.

The concentration of salt changes as the pure water flows in and the salt water flows out. So the change in concentration, where y is the concentration of salt in the tank, is $\frac{dy}{dt}$ . Thus, the change in the concentration of salt is found in

$\frac{dy}{dt}=$ inflow of salt - outflow of salt

Pure water, what is flowing into the tank, has no salt in it at all; and since we don't know how much salt is leaving (our unknown, basically), the outflow at 3 gal/min is 3 times the amount of salt leaving out of the 400 gallons of salt water at time t:

$3(\frac{y}{400})$