3 years ago

Which of the following traversals would print all of the elements in the 2D array of integers nums

Computers and Technology

1 answer:

adoni [48]3 years ago

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Answer:

This is from three days ago im

guessing you got the answer if you can get it to me that would be awesome

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. (a) Prove or disprove carefully and in detail: (i) Θ is transitive and (ii) ω is transitive. (b) Assume n is a positive intege

Sergio [31]

Answer:

The Following are the solution to this question:

Explanation:

In Option a:

In the point (i) $\Omega$ is transitive, which means it converts one action to others object because if $\Omega(f(n))=g(n)$ indicates $c.g(n)$ . It's true by definition, that becomes valid. But if $\Omega(g(n))=h(n)$ , which implies $c.h(n)$ . it's a very essential component. If $c.h(n) < = g(n) = f(n) \$ . They $\Omega(f(n))$ will also be $h(n)$ .

In point (ii), The value of $\Theta$ is convergent since the $\Theta(g(n))=f(n)$ . It means they should be dual a and b constant variable, therefore $a.g(n)$ could only be valid for the constant variable, that is $\frac{1}{a}\ \ and\ \ \frac{1}{b}$ .

In Option b:

In this algorithm, the input size value is equal to 1 object, and the value of A is a polynomial-time complexity, which is similar to its outcome that is $O(n^{2})$ . It is the outside there will be a loop(i) for n iterations, that is also encoded inside it, the for loop(j), which would be a loop $(n^{2})$ . All internal loops operate on a total number of $N^{2}$ generations and therefore the final time complexity is $O(n^{2})$ .