1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
RUDIKE [14]
2 years ago
12

8)

Mathematics
1 answer:
mixer [17]2 years ago
6 0
Did you already find the answer?
You might be interested in
Draw the figure with their measurements and find their volume
babunello [35]

1) Volume = L × W × H = 8 × 3 × 5 = <u>120 m³</u>

2) Volume = s³ = 17³ = 17 × 17 × 17 = <u>4913 cm³</u>

3) Volume = s³ = 30³ = 30 × 30 × 30 = <u>27000 cm³</u>

4) Volume = L × W × H = 13 × 5 × 7 = <u>455 cm³</u>

5) Volume = s³ = 15³ = 15 × 15 × 15 = <u>3375 cm³</u>

<u />

Formula's applied:

(a) Volume of rectangle: Length × Width × Height

(b) Volume of Cube: (side)³

5 0
2 years ago
Please help and show work <br> i need 17 19 and 21
Nat2105 [25]

Answer:

Step-by-step explanation:

<em>(17).</em> g(x) = x³ + 4x

f(x) = 4x + 1

( f × g )( x ) = ( x³ + 4x )( 4x + 1 ) = <em>4 </em>x^{4}<em> + x³ + 16x² + 4x</em>

<em>(19).</em> f(t) = 4t - 4

g(t) = t - 2

( 4f + 3g )( t ) = 4(4t - 4) + 3(t - 2) = 16t - 16 + 3t - 6 = <em>19t - 22</em>

<em>(21).</em> h(t) = t + 3

g(t) = 4t + 1

h(t - 2) + g(t - 2) = ( t - 2 ) + 3 + 4( t - 2 ) + 1 = t + 4t - 2 + 3 - 8 + 1 = <em>5t - 6</em>

5 0
3 years ago
What is the answer for cos(43) = sin(?)
oee [108]

Answer:

Step-by-step explanation:

cos 43=cos (90-47)=sin 47

6 0
2 years ago
My watch is 5 minutes slow, but i think it is 3 minutes fast. I arrive 'on time' according to my calculations to catch the 1:15
faltersainse [42]
1:15 pm + 5 minutes =1:20 PM  You add 5 minutes because your watch is slow then subtract 3 minutes because you thought the watch was 3 minutes fast. real time is 1:17 PM
 1:20 pm  - 3 minutes = 1:17 PM
4 0
3 years ago
19. For the following exercises, use the descriptions of each pair of lines given below to find the slopes of Line 1 and Line 2.
worty [1.4K]

Answer:

The given lines are un-related.

Step-by-step explanation:

In the question, two lines are given as line 1 passes through (-8,-55) and (10,89). Whereas, line 2 passes through (9,-44) and (4,-14).

It is required to find the slope of given lines and figure out whether they are perpendicular, parallel or neither.

To solve this question, first find the slope of both lines. Check if their product is equal to -1, then they are perpendicular. If the slopes are equal the lines are parallel.

Step 1 of 2

Find the slope of first line.

$$\begin{aligned}&m_{1}=\frac{89-(-55)}{10-(-8)} \\&m_{1}=\frac{144}{18} \\&m_{1}=8\end{aligned}$$

Step 2 of 2

Find the slope of first line.

$$\begin{aligned}&m_{2}=\frac{-14-(-44)}{4-9} \\&m_{2}=\frac{30}{-5} \\&m_{2}=-6\end{aligned}$$

Since, both slopes are neither equal nor reciprocal of each other.

Therefore, the lines are un-related.

4 0
1 year ago
Other questions:
  • 100 yd equals how many in
    6·1 answer
  • Find the discriminant of x^2+6x+13=0. What does this number tell you about how many real solutions there are to the equation? Sh
    12·2 answers
  • Write the number that can be shown with this many hundreds ten one hundred 1 ten 2 18 one
    12·1 answer
  • PLZZ HELP ME I'LL FAN U N GIVE YOU A MEDAL
    5·1 answer
  • Joy wants to buy strawberries and raspberries to bring to a party. Strawberries cost $1.60 per pound and raspberries cost $1.75
    10·1 answer
  • The ratio of the perimeters of two rectangles is 4 to 7. The perimeter of the larger rectangle is 42 inches. Solve for the perim
    5·2 answers
  • What is the value of the expression. -8-(-3) <br> = -8 blank 3 <br> = blank
    13·1 answer
  • PLEASE HELP ME I WILL GIVE YOU EXTRA POINTS.
    12·2 answers
  • What is the solution to the equation 3(y-2)=2y-8 A.-2/5 B.-14 C. -2 D. -2 4/5 I NEED-HELP PLeAse
    6·1 answer
  • −2/3x = 10y – 2 written in standard form
    12·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!