Answer:
the rate compounded semi-annually is compounded twice in a year. thus, this rate is higher than the rate compounded annually which is compounded once in a year
Step-by-step explanation:
The formula for calculating future value:
FV = P (1 + r/m)^mn
FV = Future value
P = Present value
R = interest rate
N = number of years
m = number of compounding
For example, there are two banks
Bank A offers 10% rate with semi-annual compounding
Bank B offers 10% rate with annual compounding.
If you deposit $100, the amount you would have after 2 years in each bank is
A = 100x (1 + 0.1/2)^4 = 121.55
B = 100 x (1 + 0.1)^2 = 121
The interest in bank a is 0.55 higher than that in bank B
Answer:
Step-by-step explanation:
b would be 0
your slope is rise/run. up one and over three. up one and over three. so 1/3
write it as y=1/3x+0, or y=1/3x
Answer:
y=-3/2x+4
Step-by-step explanation:
In order to solve this you need to graph the points and then draw a line threw them. The place where the line crosses through the y-intercept is the value for b in y=mx+b.
Answer:
a)
a1 = log(1) = 0 (2⁰ = 1)
a2 = log(2) = 1 (2¹ = 2)
a3 = log(3) = ln(3)/ln(2) = 1.098/0.693 = 1.5849
a4 = log(4) = 2 (2² = 4)
a5 = log(5) = ln(5)/ln(2) = 1.610/0.693 = 2.322
a6 = log(6) = log(3*2) = log(3)+log(2) = 1.5849+1 = 2.5849 (here I use the property log(a*b) = log(a)+log(b)
a7 = log(7) = ln(7)/ln(2) = 1.9459/0.6932 = 2.807
a8 = log(8) = 3 (2³ = 8)
a9 = log(9) = log(3²) = 2*log(3) = 2*1.5849 = 3.1699 (I use the property log(a^k) = k*log(a) )
a10 = log(10) = log(2*5) = log(2)+log(5) = 1+ 2.322= 3.322
b) I can take the results of log n we previously computed above to calculate 2^log(n), however the idea of this exercise is to learn about the definition of log_2:
log(x) is the number L such that 2^L = x. Therefore 2^log(n) = n if we take the log in base 2. This means that
a1 = 1
a2 = 2
a3 = 3
a4 = 4
a5 = 5
a6 = 6
a7 = 7
a8 = 8
a9 = 9
a10 = 10
I hope this works for you!!
