The probability of getting a cookie with no more than 3 chips is 0.714.
<h3>What is probability?</h3>
It is defined as the ratio of the number of favorable outcomes to the total number of outcomes, in other words, the probability is the number that shows the happening of the event.
We have:
Well-mixed cookie dough will produce cookies with a mean of 6 chocolate chips apiece.
Using poison ratio:

λ is the mean number of chocolate chips in a piece

P(X ≥ 5) = 1 - P(X < 5)
P(X ≥ 5) = 1 - P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4)
![\rm P(X \geq 5) = 1-[\dfrac{6^0 e^{-6}}{0!}+\dfrac{6^1 e^{-6}}{1!}+\dfrac{6^2 e^{-6}}{2!}+\dfrac{6^3 e^{-6}}{3!}+\dfrac{6^4 e^{-6}}{4!}]](https://tex.z-dn.net/?f=%5Crm%20P%28X%20%5Cgeq%20%205%29%20%20%3D%20%201-%5B%5Cdfrac%7B6%5E0%20e%5E%7B-6%7D%7D%7B0%21%7D%2B%5Cdfrac%7B6%5E1%20e%5E%7B-6%7D%7D%7B1%21%7D%2B%5Cdfrac%7B6%5E2%20e%5E%7B-6%7D%7D%7B2%21%7D%2B%5Cdfrac%7B6%5E3%20e%5E%7B-6%7D%7D%7B3%21%7D%2B%5Cdfrac%7B6%5E4%20e%5E%7B-6%7D%7D%7B4%21%7D%5D)
After solving;
P(X ≥ 5) = 0.714
Thus, the probability of getting a cookie with no more than 3 chips is 0.714.
Learn more about the probability here:
brainly.com/question/11234923
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Answer:
6
Step-by-step explanation:
g(f(0)) means that the input of f(x) is 0 and this value of f(x) found is the input of g(x). This is known as composite functions.
Let's find the value of f(0).
f(x)= x²
f(0)= 0²
f(0)= 0
Now, we can find the value of g(f(0)).
g(x)= x +6
g(f(0))
= g(0)
= 0 +6
= 6
All you need for a point to be left unchanged is it being on the line of reflection. (Generally speaking)
The first one is wrong cause you can have a line of reflection anywhere. If the line is horizontal ( x axis) then the slope would be zero. Whereas a line on y axis would be an undefined slope. There are also diagonal lines of reflections which have slopes
I am pretty sure the second one would be correct because, as previously stated, all the line needs to stay in the same place is it being on the line of reflection.
Again, lines of reflection do not have a set slope, a diagonal line of reflection going like / on the chart through the axis could have a slope of one, but it is not needed for the point to remain in the same place
The point does not necessarily need to be on the origin, it can be anywhere on the line of reflection, and if the line of reflection does not pass through the origin, a point on the origin would be moved in a reflection.
I hope this makes sense and helps you out a bit... have a good day
The intercepts and the graph on your worksheet are not correct. Please see below for details:
has solutions at x=-1 and x=3 (use the quadratic formula to solve). That means these are the x-intercepts, namely points:
(-1,0) and (3,0).
The y-intercept comes from setting x=0 and calculating the y value:

so the y-intercept is (0,-3).
Now to the graph: Based on the form of the function we can see this is a quadratic function and its graph will be a parabola. You can reformat the expression in the following form

and that will indicate that the apex of the parabola (open up) will be at the point (1,-4).
Knowing the apex, the x intercepts, and the y intercept, we can graph it now.
Graph is in the image attached.