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2 years ago

What is the slope OF THE GRAPH, not what is A slope, what is THE slope

Mathematics

2 answers:

Elenna [48]2 years ago

4 0

Answer:

the slope of this graph is $-\frac{3}1}$

Step-by-step explanation:

You can find the slope by choosing any two ordered pairs in this case I choose (2,-4) and (-1,1). The you find the run and rise. Slope= $\frac{rise}{run}$ , the run was 3 up and the run was 1. And it is negative because it is going down to the right.

Oksanka [162]2 years ago

3 0

Answer:

-3/1

Step-by-step explanation:

The slope can be found by putting the rise over the run.

Pick 2 points on the graph that intercept the line.

I'll pick (0,2), and (1,-1)

Look at the rise.(How many places it goes up or down)

The rise vertical distance(rise), between the two points is -3.

Now look at the run(the horizontal distance.) It's 1.

Rise/Run = -3/1 AKA -3

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A bus travels 12 miles in 20 minutes at this rate how many miles does the bus travel in 60 minutes

Dovator [93]

Answer:

If I'm answering this right, the bus should have travel 36 miles in 60 minutes.

If it takes 20 minutes to get to 12 miles then for every twenty minutes you would just add 12 miles.

3 0

2 years ago

Please help me with this soon much appreciated.

NeX [460]

Answer:

1 : 2

Step-by-step explanation:

this is a 30-60-90 triangle which is a special right triangle. the ratio of the sides is x: x*sqrt(3): 2x, in the order short leg: long leg: hypotenuse. so the ratio of the short leg to the hypotenuse is x:2x or 1:2

8 0

1 year ago

The graph below represents the solution set of which inequality?

natulia [17]

Answer:

option: B ( $x^2+2x-8$ ) is correct.

Step-by-step explanation:

We are given the solution set as seen from the graph as:

(-4,2)

On solving the first inequality we have:

$x^2-2x-8$

On using the method of splitting the middle term we have:

$x^2-4x+2x-8$

⇒ $x(x-4)+2(x-4)=0$

⇒ $(x+2)(x-4)$

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

$x+2>0$ and $x-4$

i.e. x>-2 and x<4

so we have the region as:

(-2,4)

Case 2:

$x+2$ and $x-4>0$

i.e. x<-2 and x>4

Hence, we did not get a common region.

Hence from both the cases we did not get the required region.

Hence, option 1 is incorrect.

We are given the second inequality as:

$x^2+2x-8$

On using the method of splitting the middle term we have:

$x^2+4x-2x-8$

⇒ $x(x+4)-2(x+4)$

⇒ $(x-2)(x+4)$

And we know that the product of two quantities are negative if either one of them is negative so we have two cases:

case 1:

$x-2>0$ and $x+4$

i.e. x>2 and x<-4

Hence, we do not get a common region.

Case 2:

$x-2$ and $x+4>0$

i.e. x<2 and x>-4

Hence the common region is (-4,2) which is same as the given option.

Hence, option B is correct.

$x^2-2x-8>0$

On using the method of splitting the middle term we have:

$x^2-4x+2x-8>0$

⇒ $x(x-4)+2(x-4)>0$

⇒ $(x-4)(x+2)>0$

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

$x+2>0$ and $x-4>0$

i.e. x>-2 and x>4

Hence, the common region is (4,∞)

Case 2:

$x+2$ and $x-4$

i.e. x<-2 and x<4

Hence, the common region is: (-∞,-2)

Hence, from both the cases we did not get the desired answer.

Hence, option C is incorrect.

$x^2+2x-8>0$

On using the method of splitting the middle term we have:

$x^2+4x-2x-8>0$

⇒ $x(x+4)-2(x+4)>0$

⇒ $(x-2)(X+4)>0$

And we know that the product of two quantities are positive if either both of them are negative or both of them are positive so we have two cases:

Case 1:

$x-2$ and $x+4$

i.e. x<2 and x<-4

Hence, the common region is: (-∞,-4)

Case 2:

$x-2>0$ and $x+4>0$

i.e. x>2 and x>-4.

Hence, the common region is: (2,∞)

Hence from both the case we do not have the desired region.

Hence, option D is incorrect.

5 0

2 years ago

How many shapes did you put together to make 3/2

ella [17]

You put 3 shapes together I believe

5 0

2 years ago

Answer 1-6 (about square root)

Taya2010 [7]

Answer:

1. For a cube, volume = $edge^{3}$

2. $\sqrt[3]{volume}$ = edge

3. Volume of the cube = 216 so, the edge = $\sqrt[3]{216}$ = 6

4. 1st blank = 6

2nd blank = 6

3rd blank = 216

4th blank = 216

5. 6 is the edge

6. As the room is a square and we have to find the side

Area = 121

Edge = $\sqrt[2]{121}$ = 11

If my answer helped, kindly mark me as the brainliest!!

Thank You!!

4 0

2 years ago