Answer and explanation:
Farmer's number of apples = 96 apples
Given that Farmer needs to bag the apples so that there are at least 4 apples in each bag(not less than 4 apples in each bag) and not more than 10 apples in each bag
And also all apples in each bag are equal
We need to find the numbers between 4 and 10(including 4 and 10) that can divide 96 without a remainder
4 can divide 96= 24
5 cannot divide 96 without remainder
6 can divide 96 =16
7 cannot divide 96 without remainder
8 can divide 96=12
9 cannot divide 96 without remainder
10 cannot divide 96 without remainder
From the above we see that the factors of 96 = 4, 6, 8 between 4 and 10
4 apples = 24 bags
6 apples = 16 bags
8 apples = 12 bags
Therefore, there can be 3 possible ways of having equal number of apples in each bag between 4 and 10 apples
First simplify the equation and next multiply the 20 with the x^2 and find a number that adds together to give you the middle
Answer:
3.33333333 . . .
Step-by-step explanation:
Step-by-step explanation:
The answer in the picture above
Answer:
Step-by-step explanation:
Sin(42) = n/21
n = 21 * sin(42)
n = 21 * 0.6691
n = 14.052
Cos(42) = m / 21
21 * cos(42) = m
m = 21 * 0.7431
m = 15,61
Theta + 42 = 90
Theta = 90 - 42
Theta = 48
