Ask question

Ask question

All categories

Citrus2011 [14]

3 years ago

13

(-3, 117) (0, 45) (3, 27) Quadratic regression

1 answer:

telo118 [61]3 years ago

8 0

Answer:

is it y = -15x + 63

Step-by-step explanation:

You might be interested in

Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

vodka [1.7K]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

7 0

3 years ago

it took 8 hours for karl and lou to finish a project for science class together. if karl had worked alone on the project it woul

kkurt [141]

It would take 10 hours just like it did for Karl .

4 0

4 years ago

Evaluate the expression n ÷ 5 for n = 3.2.<br><br> A. 0.064<br> B. 0.604<br> C. 0.64<br> D. 6.4

Licemer1 [7]

Answer:

n/5

substitution for n = 3.2

3.2/5

0.64

3 0

3 years ago

To get the echo of a positive integer, we write it twice in a row without a space. For example, the echo of 2022 is 20222022. Is

Lynna [10]

The <em>echo</em> number 20222022202220222022 is the <em>perfect</em> square of 4496890281.

<h3>What echo number is a perfect square</h3>

An <em>echo</em> number has a <em>perfect</em> square if its square root is also a <em>natural</em> number. After some iterations we found that <em>echo</em> number 20222022202220222022 is a <em>perfect</em> square:

$\sqrt{20222022202220222022} = 4496890281$

The <em>echo</em> number 20222022202220222022 is the <em>perfect</em> square of 4496890281. $\blacksquare$

To learn more on natural numbers, we kindly invite to check this verified question: brainly.com/question/17429689

8 0

3 years ago

Please help me, I don’t wanna fail..

balandron [24]

The answer is 8.7 cm

8 0

3 years ago

Read 2 more answers