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m_a_m_a [10]
3 years ago
14

A cyclist travels 18 km from home to the park.

Mathematics
1 answer:
LenKa [72]3 years ago
4 0

Answer: 24 km/h

Step-by-step explanation:

She traveled 18 km in 45 minutes, this could be simplified to .4 km/min or 24 km/h

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IgorLugansk [536]

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Answer:

  obtuse triangle

Step-by-step explanation:

The two shortest sides are 7, 15. Their sum is 7+15 = 22, which is longer than the longest side, so these lengths will form a triangle.

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The "form factor" can be computed to be ...

  a^2 +b^2 -c^2 . . . . . where c = longest side

This value is ...

  7^2 +15^2 -21^2 = 49 +221 -441 = -167

This negative value indicates the largest angle is more than 90°, so the triangle is obtuse.

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<em>Additional comment</em>

This "form factor" has the same sign as the cosine of the largest angle. The cosine is negative for angles greater than 90°. The cosine of the angle is ...

  "form factor"/(2ab) = -167/210

  largest angle = arccos(-167/210) ≈ 142.678°

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2 years ago
: Maria attended a Chicago Cubs baseball game last night. The ticket to get into the game was $39.00 and hot dogs cost $5.50 eac
PIT_PIT [208]

Answer: 3

Step-by-step explanation:

At first you would subtract 39 from 60. Then you would do 21/5.5 and you would get 3.818… and due to the fact you can't go over 60 you would round to 3 and not 4

8 0
3 years ago
Subtract. Susan began a trip with 18 1/2 gallons of gas in the gas tank of her car. If she used 17 3/4 gallons on the trip, how
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D. 18.5 minus 17.75 is .75
8 0
3 years ago
Read 2 more answers
How can i estimate a number from a bar graph??
olga55 [171]
You should first find out what lines are what,
Like for example, If you had 5 - 10 - 15 as the Y Lines and the bar was between 5 and 10 then your best bet would be to estimate what the middle of 5 and 10 is which would be 7 or 8.
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3 years ago
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sertanlavr [38]

In cylindrical coordinates, we take

x=r\cos\theta

y=r\sin\theta

z=z

so that \mathrm dx\,\mathrm dy\,\mathrm dz=r\,\mathrm dr\,\mathrm d\theta\,\mathrm dz.

We have

1+x^2+y^2=1+r^2

and the integral is

\displaystyle\int_0^2\int_0^\pi\int_0^1\frac r{1+r^2}\,\mathrm dr\,\mathrm d\theta\,\mathrm dz=\frac{\ln2}2\int_0^2\int_0^\pi\mathrm d\theta\,\mathrm dz=\boxed{\pi\ln2}

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3 years ago
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