The answer to your problem, I’m pretty sure the second one, I’m not to sure tho!
Answer:
![14y^{2} -64y](https://tex.z-dn.net/?f=14y%5E%7B2%7D%20-64y)
Step-by-step explanation:
Hello!
4y(5y - 11)
Distribute the 4y
4y * 5y = 20y^2
4y * -11 = -44y
Put it together
20y^2 - 44y
2y(3y + 10)
Distribute the -2y
-2y * 3y = -6y^2
-2y * 10 = -20y
Put it gether
-6y^2 - 20y
Put it all together
20y^2 - 44y - 6y^2 - 20y
Combine like terms
14y^2 - 64y
The answer is ![14y^{2} -64y](https://tex.z-dn.net/?f=14y%5E%7B2%7D%20-64y)
Hope this helps!
That depends on what the digits are. It could be anywhere between zero times and infinite times. If both are the same digit and not zero, then the tenth is ten times the size of the hundredth.
Both of the fractions can be added since they both have 8 as the denominator 3/8+5/8=8/8 which is a whole.