If we let p and t be the masses of the paper and textbook, respectively, the equations that would best represent the given in this item are:
(1) 20p + 9t = 44.4
(2) (20 + 5)p + (9 + 1)t = 51
The values of p and t from the equation are 0.6 and 3.6, respectively. Thus, each paperback weighs 0.6 pounds and each textbook weighs 3.6 pounds.
Answer:
⅓
Step-by-step explanation:
n(s) 1 die & 2 coins = 6×4 = 24
n (event) 1 head = 6 (by die) +2( by coins)
= 8
so, probability P = 8/24 = ⅓
Answer:
Time left for each question is less than 5.5 minutes
Step-by-step explanation:
Given that:
Raphael is trying to solve 5 math questions in less than 20 minutes.
3 questions have been completed which have taken 3 minutes each.
To find:
How much time is left with Raphael for each question so as to reach his goal.
Solution:
First of all, let us find the time that has been already consumed by Raphael in solving the 3 questions.
3
3 = 9 minutes
Time left = Total Time - Time already consumed
Time left = 20 - 9 = 11 minutes
Number of questions to be solved = Total questions - Questions solved
Number of questions to be solved = 5 - 3 = 2
Average time left for each question = Time left divided by Number of questions to be solved
Average time left for each question = 11
2 = 5.5 minutes
Therefore, time left for each question is less than 5.5 minutes.