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Travka [436]
3 years ago
11

Hello, my fellow brainly users I currently I'm in need of math help. The math grade is 7th. Anyone who is willing and good at ma

th is welcome plz do not join the zoom if you're not experienced or aren't gonna help it's a waste of ur and my time. Whoever helps me finish will pay pal or vevmod $120. The Z o o m meeting details are on the bottom.
Meeting ID: 945 0878 7272 Passcode: W35s6S
Mathematics
1 answer:
dalvyx [7]3 years ago
8 0
You haft to join the meet so you yah just join
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The procedure known as determines which digit at the right of the number will be the last digit displayed and increases it by on
Oduvanchick [21]
This procedure is known as estimating or rounding, where one compares the digit to the right is the number and sees whether or not is found within a given range, greater than 5 and can be used to increase the number in question, by a value of 1.
7 0
4 years ago
Wanda started walking along a path 27 seconds before Dave. Wanda walked at a constant rate of 3 feet per second. Dave walked alo
Advocard [28]

Answer:

Wanda and Dave will catch each other in 54 seconds after Dave starts walking.

Step-by-step explanation:

Let Wanda and Dave catch each other when x be the time after Dave starts walking and y be the distance covered by them

It is given that Wanda started walking along a path 27 seconds before Dave and the constant speed of Wanda is 3 feet per second.

speed=\frac{distance}{time}

3=\frac{y}{x+27}

y=3(x+27)

 y=3x+81                          .... (1)

The constant speed of Dave is 4.5 feet per second.

4.5=\frac{y}{x}

y=4.5x                                .... (2)

Equate equation (1) and (2).

3x+81=4.5x

81=1.5x

Divide both sides by 1.5.

\frac{81}{1.5}=x

54=x

Therefore, Wanda and Dave will catch each other in 54 seconds after Dave starts walking.

6 0
4 years ago
7. Sky Castle Company is conducting research on 3 independent communities of 12 members each to see how they have been consuming
tresset_1 [31]

Answer:

1.98% probability that at least 11 members are categorized as low risk participants in two of three communities

Step-by-step explanation:

To solve this question, we need to use two separate binomial trials.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Probability of at least 11 members being categorized as low risk participants.

12 members in the sample, so n = 12

30% chance to be categorized as high risk participants. So 100-30 = 70% probability of being categorized as low risk participants. So p = 0.7

This probability is

P(X \leq 11) = P(X = 11) + P(X = 12)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{12,11}.(0.7)^{11}.(0.3)^{1} = 0.0712

P(X = 2) = C_{12,12}.(0.7)^{12}.(0.3)^{0} = 0.0138

P(X \leq 11) = P(X = 11) + P(X = 12) = 0.0712 + 0.0138 = 0.0850

What is the probability that at least 11 members are categorized as low risk participants in two of three communities?

For each community, 8.50% probability of at least 11 members being categorized as low risk. So p = 0.085

Three comunities, so n = 3

This probability is P(X = 2).

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 2) = C_{3,2}.(0.085)^{2}.(0.915)^{1} = 0.0198

1.98% probability that at least 11 members are categorized as low risk participants in two of three communities

6 0
3 years ago
Can someone please help me.. answer choices below<br> A.46<br> B.134<br> C.136<br> D.146
Vesnalui [34]
C b/c 180° - 44° = 136°. Angles DEB & AED add up to 180° b/c they are supplementary angles.
3 0
3 years ago
Read 2 more answers
The school you want to go to has an acceptance rate of 12%. That means that 12% of the students who apply to the school get in.
lana66690 [7]
I think the answer is 2688
7 0
3 years ago
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