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suter [353]
2 years ago
12

Tia cut a 4-meter 8-centimeter wire into 10 equal pieces. Marta cut a 540-centimeter wire into 9 equal pieces. How much longer i

s one of Marta’s wires than one of Tia’s?
First, Tia’s wire is 4 meters and 8 centimeters long, so that means it’s 408 centimeters long, then you divide that by 10:
tia = 408/10 = 40.8 cm

Now, Marta’s wire is 540 centimeters long and we have to divide that into 9 pieces:
Marta = 540/9 = 60 cm

Finally subtract Marta’s and Tia’s pieces: 60 - 40.8 = 19.2
So Marta’s pieces are 19.2 centimeters longer than Tia’s
Mathematics
1 answer:
bearhunter [10]2 years ago
4 0

Answer:

19.2

Step-by-step explanation:

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Answer:

The simplified expression to the given expression is \frac{4x^6}{y^2}

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Step-by-step explanation:

Given fractional expression is \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}

To simplify the given expression as below :

\frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}

=\frac{2(2x^3y^4)^4}{(2x^2y^6)^3}

=\frac{2[(2)^4(x^3)^4(y^4)^4]}{(2)^3(x^2)^3(y^6)^3}  ( using the property (a^m)^n=a^{mn})

=\frac{2[(2)^4(x^{12})(y^{16})]}{(2)^3(x^6)(y^{18})}

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Therefore the simplified expression is \frac{4x^6}{y^2}

Therefore \frac{4(2x^3y^4)^4}{2(2x^2y^6)^3}=\frac{4x^6}{y^2}

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