All categories

3 years ago

Drag a number into each line to create an equation that is true for all values of x

Mathematics

1 answer:

bazaltina [42]3 years ago

8 0

Answer:

blank 1 = 24

blank2= 30

Step-by-step explanation:

Given:

2(4x+3)(3x+5)

=2(12x^2+20x+9x+15)

=2(12^2+29x+15)

=24x^2+58x+30

Hence blank 1= 24 and blank2= 30 !

You might be interested in

2. Lawn tickets cost $30 each and seat tickets cost $50

Andreas93 [3]

Okay so.
If lawn tickets are $30 and seat tickets are $50 and they sold 200 seat tickets.
50 multiplied by 200 is = $ 10,000
And the goal is $14,000.
So $14,000 subtract $10,000 is $4000
$4000 is how much they made in Lawn Tickets. In order to calculate how much lawn tickets were sold, is dividing $4000 by $30 since lawn tickets are $30.
4000 divided by $30 = 133
Not sure if this is correct but all the working and steps are correct! Hope this helps.

6 0

2 years ago

Draw the multiplication table on the P=(3,5,7,9) in module 12

Lisa [10]

Answer:

Find the attached file for the solution

Step-by-step explanation: To draw the multiplication table on the P=(3,5,7,9) in module 12, create the table where all the given parameters will be at the top of horizontal axis and vertical axis,

When multiply by each other, any value that is below 12 will be written down while the value greater than 12 will be divided by 12 and the remainder will be written down.

Find the attached file for the solution and table.

8 0

2 years ago

I know that x=0 but I don't know how I really got that.

galina1969 [7]

Sqrt(x+4-3)=1
sqrt (x+1) = 1
x+1 = 1^2
x=1-1
x=0

This is how you would get x=0

Hope I helped :)

8 0

3 years ago

Jane paid $35 for her meal. If the cost of the meal was $30 , what was the tax rate.

marta [7]

5 dollars because she paid 30 for the meal

6 0

2 years ago

Read 2 more answers

Complete the square to the problem X^2+6x-16=0

marishachu [46]

Answer:

Step-by-step explanation:

$(a+b)^2=a^2+2ab+b^2\qquad(*)\\\\-------------------------------\\\\x^2+6x-16=0\qquad\text{add 16 to both sides}\\\\x^2+6x=16\\\\x^2+2(x)(3)=16\qquad\text{add}\ 3^2\ \text{to both sides}\\\\\underbrace{x^2+2(x)(3)+3^2}_{(*)}=16+3^2\\\\(x+3)^2=16+9\\\\(x+3)^2=25\Rightarrow x+3=\pm\sqrt{25}\\\\x+3=-5\ \vee\ x+3=5\qquad\text{subtract 3 from both sides}\\\\\boxed{x=-8\ \vee\ x=2}$

3 0

3 years ago