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vlada-n [284]
3 years ago
14

Zeb wants to make the world's longest shoelace. He has a shoelace that is 22 cm long and another shoelace that is 7 cm longer th

an the first shoelace.
How long would Zeb's shoelace be if he lined the two laces up end to end?
Mathematics
2 answers:
yawa3891 [41]3 years ago
7 0

The correct answer would be 51 cm.

Hope this helps.

Inessa [10]3 years ago
7 0
First shoelace- 22 cm
Second shoelace- 7+22= 29
Total length of combined shoelaces- 22+29=51
51 cm is the total length of the two combined shoelaces.

Hope this helps! I would greatly appreciate a brainliest! :)
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Answer:

C. y<3

Step-by-step explanation:

We are required to determine the solution set of the inequality

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Step 1: Add 9 to both sides

15y-9+9

Step 2: Divide both sides by 15

15y \div 15

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The correct option is C.

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Circle P is described by the equation (x−1)2+(y+6)2=9 and circle Q is described by the equation (x+4)2+(y+14)2=4. Select from th
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Answer:

(a) Circle Q is 9.4 units to the center of circle P

(b) Circle Q has a smaller radius

Step-by-step explanation:

Given

P:(x - 1)^2 + (y + 6)^2 = 9

Q:(x + 4)^2 + (y + 14)^2 = 4

Solving (a): The distance between both

The equation of a circle is:

(x - h)^2 + (y - k)^2 = r^2

Where

Center: (h,k)

Radius:r

P and Q can be rewritten as:

P:(x - 1)^2 + (y + 6)^2 = 3^2

Q:(x + 4)^2 + (y + 14)^2 = 2^2

So, for P:

Center = (1,-6)

r = 3

For Q:

Center = (-4,-14)

r = 2

The distance between them is:

d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2

Where:

Center = (1,-6) --- (x_1,y_1)

Center = (-4,-14) --- (x_2,y_2)

So:

d = \sqrt{(1 - -4)^2 + (-6 - -14)^2

d = \sqrt{(5)^2 + (8)^2

d = \sqrt{25 + 64

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Solving (b): The radius;

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r = 3 --- circle P

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By comparison

2 < 3

<em>Hence, circle Q has a smaller radius</em>

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