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3 years ago

HELPPPP! ILL GIVE YOU BRAINLIEST!

Mathematics

2 answers:

Mademuasel [1]3 years ago

7 0

Answer:Can you put the question?? Thank You

Step-by-step explanation:

Vlad [161]3 years ago

5 0

Answer:

what can i help with?

Step-by-step explanation:

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At a specific point on a highway, vehicles arrive according to a Poisson process. Vehicles are counted in 12 second intervals, a

morpeh [17]

Answer: a) 4.6798, and b) 19.8%.

Step-by-step explanation:

Since we have given that

P(n) = $\dfrac{15}{120}=0.125$

As we know the poisson process, we get that

$P(n)=\dfrac{(\lambda t)^n\times e^{-\lambda t}}{n!}\\\\P(n=0)=0.125=\dfrac{(\lambda \times 14)^0\times e^{-14\lambda}}{0!}\\\\0.125=e^{-14\lambda}\\\\\ln 0.125=-14\lambda\\\\-2.079=-14\lambda\\\\\lambda=\dfrac{2.079}{14}\\\\0.1485=\lambda$

So, for exactly one car would be

P(n=1) is given by

$=\dfrac{(0.1485\times 14)^1\times e^{-0.1485\times 14}}{1!}\\\\=0.2599$

Hence, our required probability is 0.2599.

a. Approximate the number of these intervals in which exactly one car arrives

Number of these intervals in which exactly one car arrives is given by

$0.2599\times 18=4.6798$

We will find the traffic flow q such that

$P(0)=e^{\frac{-qt}{3600}}\\\\0.125=e^{\frac{-18q}{3600}}\\\\0.125=e^{-0.005q}\\\\\ln 0.125=-0.005q\\\\-2.079=-0.005q\\\\q=\dfrac{-2.079}{-0.005}=415.88\ veh/hr$

b. Estimate the percentage of time headways that will be 14 seconds or greater.

so, it becomes,

$P(h\geq 14)=e^{\frac{-qt}{3600}}\\\\P(h\geq 14)=e^{\frac{-415.88\times 14}{3600}}\\\\P(h\geq 14)=0.198\\\\P(h\geq 14)=19.8\%$

Hence, a) 4.6798, and b) 19.8%.

7 0

3 years ago

(PLS help I’ll give brainliest to whoever can answer right nobody has been able to. )

natali 33 [55]

Volume of a cone = 3.14 x 0.75^2 x 2/3
= 3.14 x 0.5625 x 2/3
= 1.76625 x 2/3
= 1.1775 = 1.18 feet^3

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2 years ago

DAY 27, MAY 7, 2020

KengaRu [80]

If I’m not mistaken, the answer is C.

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natulia [17]

Answer: Light waves

Step-by-step explanation:

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nikitadnepr [17]

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