HELPPPP! ILL GIVE YOU BRAINLIEST!

When I solve this problem I get a big number, and I don't kwow if it's Ok:

Jlenok [28]

Answer:

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Step-by-step explanation:

6 0

3 years ago

Joey and Armando live on the same st as the park. The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando'

AleksandrR [38]

Let's start by assuming Armando's house is between Joey's and the park.

Let $x$ be the distance Joey walked to Armando's house.

<span>The park is 9/10 mile from Joey's home. Joey leaves home and walks to Armando's home. Then Joey and Armando walk 3/5 mile to the park.

</span> $\dfrac{9}{10} = x + \dfrac{3}{5}$

$x = \dfrac{9}{10} - \dfrac{3}{5} = \dfrac{9}{10} -\dfrac{6}{10} = \dfrac{3}{10}$

That's probably the answer they're looking for. But what if the park is between Joey and Armando's houses or Joey is between the park and Armando? (The latter isn't really possible with the given distances.)

Let $a, b, c$ be the distances between three collinear points like we have here. Our equation is really a few equations in one, something like

$\pm a \pm b = \pm c$

Let's get rid of the plus/minuses. Squaring,

$a^2 + b^2\pm 2ab = c^2$

$\pm 2ab = c^2-a^2-b^2$

$4a^2b^2 = (c^2-a^2-b^2)^2$

For us, that's a quadratic equation for $c^2$

$4(9/10)^2(3/5)^2= (c^2-(9/10)^2 - (3/5)^2)^2$

I'll skip right to the solutions,

$c^2=\dfrac{9}{100} \textrm{ or } c^2=\dfrac{9}{4}$

$c=\dfrac{3}{10} \textrm{ or } c=\dfrac{3}{2}$

We could have gotten the 3/2 just by adding 9/10+3/5 but this was more fun.

6 0

3 years ago

2 trains leave the station at the same time. Train A is traveling 16 miles slower than train B. The two trains are 720 miles apa

Ber [7]

Answer: the rate of speed for train A is 66 miles per hour.

Step-by-step explanation:

Let x represent the speed of train B.

2 trains leave the station at the same time. Train A is traveling 16 miles per hour slower than train B. This means that the speed of train A would be x - 16 miles per hour.

The two trains are 720 miles apart after 4 hours. It means that both trains traveled a total distance of 720 miles in 4 hours.

Distance = speed × time

Distance travelled by train A after 4 hours is

4(x - 16) = 4x - 64

Distance travelled by train B after 4 hours is

4 × x = 4x

Since the total distance travelled by both trains is 720 miles, then

4x - 64 + 4x = 720

8x = 720 - 64 = 656

x = 656/8 = 82 miles per hour

The speed of train A would be

82 - 16 = 66 miles per hour.

6 0

3 years ago

Select the appropriate technique with the problem you are looking for.

Alenkinab [10]

Answer:

A, B, C, D

Step-by-step explanation:

(A) Checking the Equal Variance Assumption, the appropriate technique to use is:

- The ANOVA (Analysis of Variance) F test

- Plot residuals against fitted values

(B) Checking the Normal Assumption, the appropriate techniques to use are:

- Test for Kurtosis & Skewness

- Kolmogorov-Smirnov Test

- Q-Q Plots (the graphical method) also known as Quantile Plot

- Do not use a histogram; it is not advisable

(C) Checking for Model Misspecification, the appropriate techniques to use are:

- The Ramsey Regression Specification Error Test; also called RESET

- The Davidson & MacKinnon J. Test

(D) Checking for dependent errors, the appropriate technique to use is:

- Plot residuals against time variables

6 0

2 years ago

Darlene has 59 pages to type. so far she gas type 23 pages. what fraction of the job is finished

coldgirl [10]

Answer:

$\frac{23}{59}$

Step-by-step explanation:

A fraction can be found be taking the current amount over the total amount:

$\frac{current}{total}=\frac{23}{59}$

Since Darlene has only typed 23 pages out of 59, her fraction is 23 over 59. Fractions must always be in simplest form, which means that both the numerator and denominator can no longer be divided by the same factor. Since the numbers 23 and 59 are both prime and have no other factors other than 1 and themselves, the fraction 23/59 is in simplest form.

4 0

3 years ago