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alexdok [17]
2 years ago
8

What is true about the dilation? A large parallelogram is the pre-image and a smaller parallelogram is the image. It has a scale

factor between zero and one and is a reduction. It has a scale factor greater than one and is a reduction. It has a scale factor between zero and one and is an enlargement. It has a scale factor greater than one and is an enlargement.
Mathematics
2 answers:
kotegsom [21]2 years ago
8 0

Answer:

- It is a reduction with a scale factor between 0 and 1.

- It is an enlargement with a scale factor greater than 1.

Step-by-step explanation:

1. Dilation is defined as a transformation of an image in which the size on this image changes but its shape does not change.

2. In dilation, to obtain the new dimensions of the image you must multiply the dimensions of the original image by a number called "Scale factor".

3. When the scale factor is greater than 1 it is an enlargement and when this is between 0 and 1, it is a reduction.

nignag [31]2 years ago
7 0

Answer:

A

Step-by-step explanation:

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sweet-ann [11.9K]

Answer: bottom left

4x+2y+15

Step-by-step explanation:

3x + x=4x

5 + 10= 15

2y=2y

4x+2y+15

6 0
2 years ago
Read 2 more answers
A box contains 12 balls of which 5 are red, and 7 are blue. If 4 balls are drawn from the box, in how many ways can this be done
mash [69]

Answer:

175 ways

Step-by-step explanation:

5 balls are red, and 7 balls  are blue making a total of 12 balls.

4 balls are drawn from the box,

1 ball is red and 3  balls are blue out of the 4 drawn from the box.

We have to choose 1 ball from 5 red balls and 3 blue balls from 7 blue balls.

Since the order is not essential we use combinations to find out

5C1 * 7C3= 5*35 = 175 ways

6 0
3 years ago
The 12th term of a sequence is 41 and the 15th term is 140. What is the nth term?
OLga [1]
An= mth term.
an=a₁+(n-1)*d

a₁₂=41
a₁₅=140

a₁₂=41
41=a₁+(12-1)*d
41=a₁+11d 
a₁+11d=41    (1)

a₁₅=140
140=a₁+(15-1)*d
140=a₁+14d 
a₁+14d=140    (2)

With the equiations (1) and (2)  build a system of equations
a₁+11d=41
a₁+14d=140

we solve it.
-(a₁+11d=41)
  a₁+14d=140
--------------------
       3d=99  ⇒d=99/3=33

a₁+11d=41
a₁+(11*33)=41
a₁+363=41
a₁=41-363=-322

an=a₁+(n-1)*d
an=-322+(n-1)*33
an=-322+33n-33
an=-355+33n

an=-355+33n

To check:
a₁₂=-355+33*12=-355+396=41
a₁₅=-355+33*15=-355+495=140.
3 0
3 years ago
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jeyben [28]

Answer:

I added a picture, with the answers. I hope it’s good.

Step-by-step explanation:

3 0
3 years ago
What is the missing equation N÷6=8
solong [7]
48.

N/6 = 8
48/6 = 8
8 = 8
8 does indeed equal 8

Good luck! 


3 0
3 years ago
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