Answer:
![h(x)=\sqrt[3]{x+2}](https://tex.z-dn.net/?f=h%28x%29%3D%5Csqrt%5B3%5D%7Bx%2B2%7D)
Step-by-step explanation:
we have
![f(x)=\sqrt[3]{x}](https://tex.z-dn.net/?f=f%28x%29%3D%5Csqrt%5B3%5D%7Bx%7D)
The inflection point of f(x) is the point 
The inflection point of h(x) is the point 
-----> see the given graph
so
the rule of the translation of f(x) to h(x) is
That means------> The translation is 
units to the left
therefore
The equation of h(x) is equal to
1 out of 4 I'm pretty sure
If the question is to find the slope-intercept form of both lines, here's the answer:
Both lines pass through the point (-3,-4), so we can use these coordinates in both equations. The slope-intercept form is represented by y=mx+b, with m the slope, b the intersection of the line with Y'Y for x=0, y and x the coordinates of a point.
Let's first apply all these for the first line, with a slope of 4.
y = mx + b
y=-3; x=-4; m=4. All we need to do is find b.
-3 = 4(-4) + b
-3 = -16 + b
b=13
So the equation of the first line is y= 4x + 13.
Now, we'll do the same thing but for the second line:
y=-3; x=-4; m=-1/4, and we need to find b.
-3 = (-1/4)(-4) + b
-3 = 1 + b
b= -4
So the equation of the second line is y=(-1/4)x - 4
Hope this Helps! :)
5*5+5=30
5*5-15=10
30/10= 3
