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snow_tiger [21]

3 years ago

15

How many kilojoules of heat are involved in condensing 8.47 g of ammonia? (use a negative sign to indicate direction--if necessa

ry)

1 answer:

noname [10]3 years ago

5 0

Answer:

i dont know

Explanation:

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What type of physical change is it when a liquid turns into a solid and a solid turns into a liquid

goblinko [34]

Answer:

Freezing and Melting (Fusion)

Explanation:

4 0

3 years ago

Darwin called this idea of certain traits being selected in order for an organism to reproduce sexual selection. In crickets and

tamaranim1 [39]

Th correct answer is option C. Calling can be hazardous because it also attracts parasites and predators.

The mating call is used by the males to attract females for sexual reproduction. By using vocal sounds males are not only making themselves attractive to females, they are also making themselves vulnerable to predators.

Thus the mating call can have a disastrous effect on the survival of the species.

7 0

3 years ago

Read 2 more answers

For the reaction at 298 K, 2NO2(g) N2O4(g) the values of ΔH° and ΔS° are -58.03 kJ and -176.6 J/K, respectively. Calculate the v

Ierofanga [76]

Answer:

$\Delta G^o=-5.4032 kJ$

The temperature for $\Delta G^o=0[/tex is [tex]T=328.6 K$

Explanation:

The three thermodinamic properties (enthalpy, entropy and Gibbs's energy) are linked in the following formula:

$\Delta G^o=\Delta H^o + T*\Delta S^o$

Where:

$\Delta G^o$ is Gibbs's energy in kJ

$\Delta H^o$ is the enthalpy in kJ

$\Delta S^o$ is the entropy in kJ/K

$T$ is the temperature in K

Solving:

$\Delta G^o=-58.03 kJ - 298K*-0.1766 kJ/K$

$\Delta G^o=-5.4032 kJ$

For $\Delta G^o=0$ :

$0=\Delta H^o - T*\Delta S^o$

$\Delta H^o= T*\Delta S^o$

$T=\frac{\Delta H^o}{\Delta S^o}$

$T=\frac{-58.03 kJ}{-0.1766 kJ/K}$

$T=328.6 K$

3 0

3 years ago

Read 2 more answers

The diameter of a hydrogen atom is 106 pm. Find the length in kilometers of a row of 4.34 x 1023 hydrogen atoms?

valina [46]

The length in kilometers of a row of 4.34 x 1023 hydrogen atoms is 4.34 x 10¹⁴ km.

<h3>Length of the entire hydrogen atoms</h3>

The length of the entire hydrogen atom is calculated as follows;

Length of the row = number x diameter of one

Length of the row = 4.34 x 10²³ x 10⁶ x 10⁻¹²

Length of the row = 4.34 x 10¹⁷ m

Length of the row = 4.34 x 10¹⁴ km

Thus, the length in kilometers of a row of 4.34 x 1023 hydrogen atoms is 4.34 x 10¹⁴ km.

Learn more about diameter of hydrogen atom here: brainly.com/question/13796082

#SPJ1

3 0

3 years ago

Drive down any three characteristic of modern periodic table

Nitella [24]

Electronegativity
Atomic radius
Ionization energy

6 0

3 years ago