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3 years ago

Which result occurs during an exothermic reaction?(1 point)

Chemistry

2 answers:

vekshin13 years ago

6 0

The result which occurs during an exothermic reaction is: C. Light and heat are released into the environment.

A chemical reaction is defined as a chemical process involving the continuous transformation and rearrangement of either the ionic, atomic or molecular structure of chemical elements, especially through the breakdown and formation of chemical bonds, so as to produce a new chemical compound.

Basically, the two (2) main types of chemical reaction are;

Endothermic reaction: this is a chemical reaction in which heat is absorbed .

Exothermic reaction: this is a chemical reaction in which light and heat is liberated (released) into the environment.

In an exothermic chemical reaction, light and heat energy is liberated (released) when the energy of the products is lesser than the energy of the reactants.

In conclusion, light and heat is liberated (released) into the environment during an exothermic reaction.

Lana71 [14]3 years ago

4 0

In an exothermic reaction :

Light and heat are released into the environment.

therefore, C is correct option

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3 years ago

Assuming that the only lons contributing to the salt content in the Dead sea is Nat

marshall27 [118]

Answer:

3.37kg of NaCl is the salt content of the dead sea

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A concentration of 33.7% means there are 33.7g of NaCl in 100mL of solution.

To solve this question we need to convert 10.0L to mililiters, and then, solve for the mass of NaCl in grams and convert it to kg:

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<h3>3.37kg of NaCl is the salt content of the dead sea</h3>

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3 years ago

A) A volume of 100 mL of 1.00 M HCl solution is titrated with 1.00 M NaOH solution. You added the following quantities of 1.00 M

Wewaii [24]

Answer:

i) 5.00 mL of 1.00 M NaOH: before the equivalence point

ii) 50.0 mL of 1.00 M NaOH: before the equivalence point

iii) 100 mL of 1.00 M NaOH: at the equivalence point

iv) 150 mL of 1.00 M NaOH: after the equivalence point

v) 200 mL of 1.00 M NaOH: after the equivalence point

Explanation:

1. First calculate the number of mol acid in the 100 mL of 1.00 M HCl solution.

Equation:

Molarity = numbrer of moles of solute / volume of the solution in liters.

Thus, you need to convert each volume from mL to liters, which is done dividing by 1,000.

Naming M the molarity, n the number of moles of solute (acid or base), and V the volume in liters:

$M=n/v\implies n=M\times V=1.00M\times 0.100L=0.100mol$

2. Now calculate the number of moles of NaOH for every condition (addition)

i) 5.00 mL of 1.00 M NaOH

$n=0.00500liter\times 1.00M=0.00500molNaOH$

Since the number of moles of NaOH added (0.00500mol) is less than the number of moles of acid in the solution (0.100mol), this is before equivalence point.

ii) 50.0 mL of 1.00 M NaOH

$n=0.0500liter\times 1.00M=0.0500molNaOH$

Since the number of moles of NaOH added (0.0500mol) is less than the number of moles of acid in the solution (0.100mol), this is before equivalence point.

iii) 100 mL of 1.00 M NaOH

$n=0.100liter\times 1.00M=0.100molNaOH$

Since the number of moles of NaOH added (0.100mol) is equal to the number of moles of acid in the solution (0.100mol), this is at the equivalence point.

iv) 150 mL of 1.00 M NaOH

$n=0.150liter\times 1.00M=0.150molNaOH$

Since the number of moles of NaOH added (0.150mol) is greater than the number of moles of acid in the solution (0.100mol), this is after the equivalence point.

v) 200 mL of 1.00 M NaOH

This is more volume of NaOH, then this is also after the equivalence point.

5 0

3 years ago