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NemiM [27]
2 years ago
6

What type of bond will form between potassium and iodine

Chemistry
1 answer:
ella [17]2 years ago
5 0

Answer:

ionic bond

Explanation:

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What happens when the kinetic energy of molecules increases so much that electrons are released by the atoms, creating a swirlin
aleksandrvk [35]

Answer:

b) matter changes to plasma state.

Explanation:

5 0
3 years ago
Read 2 more answers
Calculate the mass in grams of 2.56 × 10 −3 mol of iron.
gizmo_the_mogwai [7]

Answer:

1.43 grams

Explanation:

Fe = 55.8 grams Fe = 1 mole Fe

2.56 • 10^-3 moles Fe / 1 • 55.8 grams Fe / 1 mole Fe = 1.43 grams Fe

Basically, you're just multiplying the molar mass of Fe (iron) by the moles of 2.56 • 10^-3 Fe, to find how many grams are in it.

2.56 • 10^-3 moles Fe = 1.43 grams Fe

5 0
3 years ago
Complete combustion of a 0.350 g sample of a compound in a bomb calorimeter releases 14.0 kJ of heat. The bomb calorimeter has a
dexar [7]

Answer:

Its final temperature is 25.8 °C

Explanation:

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

There is a direct proportional relationship between heat and temperature. The constant of proportionality depends on the substance that constitutes the body as on its mass, and is the product of the specific heat by the mass of the body. So, the equation that allows calculating heat exchanges is:

Q = c * m * ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation (ΔT=Tfinal-Tinitial)

When a body transmits heat there is another that receives it. This is the principle of the calorimeter. Then the heat released by the compound will be equal to the heat obtained by the calorimeter.

In this case, you know:

  • Q= 14 kJ= 14,000 J
  • c= 3.55  \frac{J}{g*C}
  • m=1.20 kg= 1200 g (1 kg=1000 g)
  • Tfinal= ?
  • Tinitial= 22.5 °C

Replacing:

14,000 J= 3.55 \frac{J}{g*C}*1200 g*(Tfinal-22.5C)

Solving:

\frac{14,000J}{3.55\frac{J}{g*C} *1200 g} =T final - 22.5C

3.3=Tfinal - 22.5 C

3.3 + 22.5=Tfinal

Tfinal= 25.8 °C

<u><em>Its final temperature is 25.8 °C</em></u>

3 0
3 years ago
Read 2 more answers
Given the following sets of values, calculate the unknown
weqwewe [10]

Answer:

3.91 L

Explanation:

Using the ideal gas law equation as follows:

PV = nRT

Where:

P = pressure (atm)

V = volume (L)

n = number of moles (mol)

R = gas law constant (0.0821 Latm/molK)

T = temperature (K)

Based on the information given in this question,

P = 5.23 atm

V= ?

n = 0.831 mol

T = 27°C = 27 + 273 = 300K

Using PV = nRT

V = nRT/P

V = (0.831 × 0.0821 × 300) ÷ 5.23

V = 20.47 ÷ 5.23

V = 3.91 L

8 0
3 years ago
Question 5(Multiple Choice Worth 3 points)
Katarina [22]

Answer:

\sqrt{ | {o2}^{2} | }  \times \frac{?}{?}  \sqrt[?]{?}  \times \frac{?}{?}  \sqrt[ |?| ]{?}  \sqrt{?}  \times  \frac{?}{?}

Explanation:

exactly

4 0
3 years ago
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