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german
3 years ago
11

Pls help i keep getting it wrong.

Mathematics
1 answer:
Oksanka [162]3 years ago
3 0
Did yhu do 5 and 8 ?
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Answer:

a. The critcal points are at

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b. Then, x = -5   is a maximum and x=3 is a minimum

c. The absolute minimum is at   x = 3  and the absolute maximum is at  x = -5.

Step-by-step explanation:

(a)

Remember that you need to find the points where

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Therefore you have to solve this equation.

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20x^2 (  x^2  +2x - 15)  = 0

And from that you would have   20x^2 = 0  , so x = 0.

And you would also have  x^2 +2x-15 = 0.

You can factor that equation as    x^2 +2x -15 = (x+5)(x-3) = 0

Therefore   x=-5 ,   x=3.

So the critcal points are at

x=0,-5,3

b.  

Remember that a function has a maximum at a critical point if the second derivative at that point is negative. Since

f''(x) = 80x^3 + 120x^2 -600x\\f''(-5) = 80(-5)^3 + 120(-5)^2 -600(-5) = -4000 < 0\\\\f''(3) = 80(3)^3 + 120(3)^2 -600(3) = 1440 > 0 \\

Then, x = -5   is a maximum and x=3 is a minimum

c.

The absolute minimum is at   x = 3  and the absolute maximum is at  x = -5.

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Use the discriminant to determine the number and type of solutions the equation has.
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Discriminant = square root (b^2 -4*a*c)
square root (64 -4*1*12) =
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Alice deposited 600 dollars in a new savings account, no other deposits were made, after 3 months interest was computed at an an
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Answer:

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Step-by-step explanation:

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