The number of students would not change between before the test and after the test. 3+8 and 4+7 both = 11 so finding out how many students would equal one ratio can then be used to find how many equal 3 and 8.
If 92 students are equal to 4 in the ratio, then 1 in the ratio is worth 23 students. This is important as then when you times 23 by 7 you find out how many students there are in the regular maths class, 161 students. Plussing these two together gives you a total of 253 students.
Using this 253 you can divide it by 11 to find out how much 1 number would be in the ratio, it equals 23. Using this you can then times 23 by both 3 and 8 to find the original class sizes, 3x23 = 69, and 23x8 = 184.
Making the origional class size of the advaced class 69 studnets, and the regular maths class size 184.
Answer:
Step-by-step explanation:
Given parameters:
Points = (1,1) and (5,-5)
Unknown:
Slope = ?
Solution:
The slope of the a line is the ratio of the rise of a line to its run.
Slope = 
x1 = 1
y1 = 1
x2 = 5
y2 = -5
Insert the parameters and solve;
Slope = 
= 
=
5 ones is the same as 5 times 1 which is 5
50 tens is the same as 50 times 10 which is 500
So 50 tens is larger than five ones. Hope that helped. Have a nice day
1963,50/8,50= 231
they need to sell 231 tickets
