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3 years ago

24-x/x = 1/2 find x please i need help

Mathematics

1 answer:

Aliun [14]3 years ago

3 0

Answer:

No Solution

Step-by-step explanation:

There are no values of x that make the equation true.

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The coordinates of which point are (–3, –6)? On a coordinate plane, point A is (negative 3, 6), point B is (negative 6, negative

julia-pushkina [17]

Answer:

Point c

Step-by-step explanation:

3 0

3 years ago

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Find the area of this shape. Round your answer to the nearest tenth

MrMuchimi

Answer:

The area of this figure is 31,29.

Step-by-step explanation:

We have to find also the area of the rectangle, then we will find the area of the circle and divide by 2 because here is a half circle.

area of the rectangle = b x h

area of the rectangle = 6 x 6

area of the rectangle = 36

diameter = 6

r = d : 2

r = 6 : 2

r = 3 ft

area of the circle = π x r²

area of the circle = 3,14 x 3 ft

area of the circle = 9,42 ft

area of half of circle = 9,42 : 2 = 4,71 ft

area of this figure = area of rectangle - area of half of the circle

area of this figure = 36 - 4,71

area of this figure = 31,29

So the area of this figure is 31,29.

I hope this is helpful. :)

3 0

3 years ago

Find the area of the rectangle with the given base and height.

asambeis [7]

Here you go there is hardly Any work to show for it

3 0

3 years ago

Find Exact Answers, Show your work. BRANLIEST ASAP!! THANK YOU

4vir4ik [10]

$$\cos\theta=\frac{\text{5}}{\text{13}}, \ \sin\theta=\frac{\text{12}}{13}, \ \tan\theta=\frac{\text{12}}{\text{5}}$

$$\sec\theta=\frac{\text{13}}{\text{5}},\ \csc \theta=\frac{\text{13}}{\text{12}} , \ \cot \theta=\frac{\text{5}}{\text{12}}$

Solution:

Given triangle is a right triangle.

Base = 5, Hypotenuse = 13, Height = ?

Height (h) = opposite

<em>In right triangle, square of the hypotenuse is equal to the sum of the squares of the other two sides.</em>

$5^2+h^2=13^2$

$25+h^2=169$

$h^2=144$

Taking square root on both sides.

h = 12

$$\cos\theta=\frac{\text{Base}}{\text{Hypotenuse}}$

$$\cos\theta=\frac{\text{5}}{\text{13}}$

$$\sin\theta=\frac{\text{Opposite}}{\text{Hypotenuse}}$

$$\sin\theta=\frac{\text{12}}{13}$

$$\tan\theta=\frac{\text{Opposite}}{\text{Base}}$

$$\tan\theta=\frac{\text{12}}{\text{5}}$

$$\sec\theta=\frac{\text{Hypotenuse}}{\text{Base }}$

$$\sec\theta=\frac{\text{13}}{\text{5}}$

$$\csc \theta=\frac{\text{Hypotenuse}}{\text{Opposite }}$

$$\csc \theta=\frac{\text{13}}{\text{12}}$

$$\cot \theta=\frac{\text{Base }}{\text{Opposite}}$

$$\cot \theta=\frac{\text{5}}{\text{12}}$

6 0

4 years ago

The temperature was 54 at 7:00 a.m. At 3:00 p.m. on the same day, the temperature was 82. What is the rate of change in temperat

vampirchik [111]

Answer:

The rate of change was 3.5 degrees / h.

Step-by-step explanation:

In order to calculate the rate of change we need to divide the variation of temperature by the variation of time. Since the time is given to us in a 12 h format (am/pm), we first need to convert it to 24 h. To do that we sum the time that is "pm" by 12, we have:

time2 = 3 + 12 = 15

Therefore the rate of change in temperature is:

rate = variation of temp / variation of time

rate = (temp final - temp init) / (time final - time init)

rate = (82 - 54) / (15 - 7) = 28 / 8 = 3.5 degrees / h

The rate of change was 3.5 degrees / h.

4 0

4 years ago