Minimum required sample size for a desired margin of error and confidence level when it is a proportion problem: n = (z2÷margin of error2)*p-hat*q-hat
The maximum value of p-hat*q-hat occurs where p-hat = .5 (found by taking the derivative of (p-hat)*(1-p-hat) and setting it equal to 0 to find the maximum. n = ( 2.5762( for 99% confidence interval)÷.0482 )*.5*.5 = 720.028 or 721
Answer:
34
Step-by-step explanation:
plug the coefficients in the equation, so
-2-2(-2)(-5)+56
Distribute the -2(-2)(-5), so it equals -20
so the equation is -2-20+56
add -20+56, so -2+36
-2+36=34
34 is your answer
Answer:
Step-by-step explanation:
Use the intercept method of graphing a straight line:
Let x = 0. We get y = 1. This is the y-intercept (0, 1).
Let y = 0. We get x = 6/11. This is the x-intercept (6/11, 0).
Plot both points and then draw a straight line through them.
Let n be the number of nickels.
Let d be the number of dimes.
Our inequality is
10d + 5n ≤ 50
Have an awesome day! :)
It is the first one, (x,y) to (-x,y) because it is going across the y axis from the positive side, so y stays the same but x becomes negative
