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Marysya12 [62]
3 years ago
11

How to solve this? Please someone help

Mathematics
2 answers:
andrey2020 [161]3 years ago
5 0
If you’re solving for x. It’s
x ≥ y −9
seropon [69]3 years ago
4 0

Answer:

Step-by-step explanation:

So the sign means that y has to be less than or equal to x plus 9

if you wanted an answer an example could be

y = 1

x = 10

this works because if implemented into the equation

1 ≤ 10 + 9 which is true

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Find the area of the triangle below.
Fiesta28 [93]

Answer:

36 ft

Step-by-step explanation:

7 0
3 years ago
Distance between (-3,1) (1,5)
Mamont248 [21]

Answer & Step-by-step explanation:

For this problem, we will use the distance formula.

d=\sqrt{(x2-x1)^2+(y2-y1)^2}

For our (x1, y1), we will use (-3, 1). For our (x2, y2), we will use (1, 5). Now let's plug in our numbers and solve the problem.

d=\sqrt{(1-(-3))^2+(5-1)^2}

d=\sqrt{4^2+4^2}

d=\sqrt{16 + 16}

d=\sqrt{32}

d=5.657

So, the distance between (-3,1) and (1,5) is 5.657 units.

5 0
3 years ago
Calculate:<br> √5/2-√5+2/2+√5
klio [65]
-√5/2+√5+1
-√5/2+2√5/2+1
√5/2+1
(√5+2)/2

4 0
3 years ago
Read 2 more answers
Which best describes the polygon whose vertices in the coordinate plane are (-2, 3), (2,3), (2, -1), (-2, 1)?
kondaur [170]

You can see the polygon in the attached figure.

It's a trapezoid, so it's not equilateral, nor regular.

4 0
3 years ago
Question 1
vivado [14]

Answer:

For Lin's answer

Step-by-step explanation:

When you have a triangle, you can flip it along a side and join that side with the original triangle, so in this case the triangle has been flipped along the longest side and that longest side is now common in both triangles. Now since these are the same triangle the area remains the same.

Now the two triangles form a quadrilateral, which we can prove is a parallelogram by finding out that the opposite sides of the parallelogram are equal since the two triangles are the same(congruent), and they are also parallel as the alternate interior angles of quadrilateral are the same. So the quadrilaral is a paralllelogram, therefore the area of a parallelogram is bh which id 7 * 4 = 7*2=28 sq units.

Since we already established that the triangles in the parallelogram are the same, therefore their areas are also the same, and that the area of the parallelogram is 28 sq units, we can say that A(Q)+A(Q)=28 sq units, therefore 2A(Q)=28 sq units, therefore A(Q)=14 sq units, where A(Q), is the area of triangle Q.

7 0
3 years ago
Read 2 more answers
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