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4 years ago

Pre Calculus:

Mathematics

2 answers:

Mademuasel [1]4 years ago

4 0

Answer:

(p-200)/30 that is the answer good luck

Gwar [14]4 years ago

3 0

Let n be a number of friends at the perty. If dinner costs $30 per person, then it cost $30n for all friends.

Robert has booked a banquet hall which costs $200, then his total expenses are $200+30n.

If the final bill is p, then p=200+30n.

Answer: p=200+30n.

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5 = 9 f 90 i rllly need help on the plz someone answer it

Vanyuwa [196]

Heyyyy

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6 0

3 years ago

True or false the values [x] and [-x] are always equal

RoseWind [281]

Answer:

If you mean |x| and |-x| yes they are equal.

Step-by-step explanation:

Brackets do not exactly specify the meaning of absolute value.

On most keyboards, above the enter button on the main keyboard part (not the keypad one) there is a back slash symbol \ and if you hold shift, there might be another symbol | which more accurately represents absolute value,

If you aren't talking about the absolute value, then no.

4 0

3 years ago

The average number of annual trips per family to amusement parks in the UnitedStates is Poisson distributed, with a mean of 0.6

IrinaK [193]

Answer:

a) 0.5488 = 54.88% probability that the family did not make a trip to an amusement park last year.

b) 0.3293 = 32.93% probability that the family took exactly one trip to an amusement park last year.

c) 0.1219 = 12.19% probability that the family took two or more trips to amusement parks last year.

d) 0.8913 = 89.13% probability that the family took three or fewer trips to amusement parks over a three-year period.

e) 0.1912 = 19.12% probability that the family took exactly four trips to amusement parks during a six-year period.

Step-by-step explanation:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Poisson distributed, with a mean of 0.6 trips per year

This means that $\mu = 0.6n$ , in which n is the number of years.

a.The family did not make a trip to an amusement park last year.

This is P(X = 0) when n = 1, so $\mu = 0.6$ .

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-0.6}*(0.6)^{0}}{(0)!} = 0.5488$

0.5488 = 54.88% probability that the family did not make a trip to an amusement park last year.

b.The family took exactly one trip to an amusement park last year.

This is P(X = 1) when n = 1, so $\mu = 0.6$ .

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 1) = \frac{e^{-0.6}*(0.6)^{1}}{(1)!} = 0.3293$

0.3293 = 32.93% probability that the family took exactly one trip to an amusement park last year.

c.The family took two or more trips to amusement parks last year.

Either the family took less than two trips, or it took two or more trips. So

$P(X < 2) + P(X \geq 2) = 1$

We want

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1) = 0.5488 + 0.3293 = 0.8781$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.8781 = 0.1219$

0.1219 = 12.19% probability that the family took two or more trips to amusement parks last year.

d.The family took three or fewer trips to amusement parks over a three-year period.

Three years, so $\mu = 0.6(3) = 1.8$ .

This is

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)$

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-1.8}*(1.8)^{0}}{(0)!} = 0.1653$

$P(X = 1) = \frac{e^{-1.8}*(1.8)^{1}}{(1)!} = 0.2975$

$P(X = 2) = \frac{e^{-1.8}*(1.8)^{2}}{(2)!} = 0.2678$

$P(X = 3) = \frac{e^{-1.8}*(1.8)^{3}}{(3)!} = 0.1607$

$P(X \leq 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) = 0.1653 + 0.2975 + 0.2678 + 0.1607 = 0.8913$

0.8913 = 89.13% probability that the family took three or fewer trips to amusement parks over a three-year period.

e.The family took exactly four trips to amusement parks during a six-year period.

Six years, so $\mu = 0.6(6) = 3.6$ .

This is P(X = 4). So

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}$

$P(X = 4) = \frac{e^{-3.6}*(3.6)^{4}}{(4)!} = 0.1912$

0.1912 = 19.12% probability that the family took exactly four trips to amusement parks during a six-year period.

4 0

3 years ago

2(p+1) = 16 p=7 p=7.5 p=8.5 p=9

kirill [66]

Answer:

$2(p + 1) = 16$

$2p + 2 = 16$

$2p = 16 - 2$

$2p = 14$

$p = \frac{14}{2}$

$p = 7$

$\blue{\mathfrak{~saraaaaaaaaahhhh}}$

7 0

3 years ago

Read 2 more answers

The formula for the circumference of a circle is c=2pir where r is the radius and c is the circumference. The equation r is r=c/

photoshop1234 [79]

Answer:

r = 8

Step-by-step explanation:

The circumference of a circle is given by :

$C=2\pi r$ ...(1)

We need to find the value of r when C = 16π

Solving equation (1)

$r=\dfrac{C}{2\pi}\\\\r=\dfrac{16\pi}{2\pi}\\\\r=8$

So, the value of r is 8. Hence, the correct option is (b).

3 0

3 years ago