Answer:
1. 474
2. 397
Step-by-step explanation:
1. If the three-digit number is xyz, then y = z + 3.
When rounded to the nearest ten and reduced by 320, the result is 150. 150 + 320 = 470, so x = 4. y = 6 if z ≥ 5, and y = 7 if z < 5.
So the number is either 463 or 474. 463 doesn't round to 470, so the answer is 474.
2. If the three-digit number is xyz, then z = x + 4. y is the largest of the three digits; since all the digits are odd, y is either 5, 7, or 9. So z is either 5 or 7, and x is either 1 or 3.
When rounded to the nearest hundred and reduced by 100, the result is 300. 100 + 300 = 400, and y > 5, so xyz is rounded up to 400, which means x = 3. So z = 7 and y = 9.
The answer is 397.
Answer: (13.4996, 32.5004)
Step-by-step explanation:
The confidence interval for mean difference is given by :-
,
where 
= sample mean difference .
= critical t value (two-tailed)
SE= Standard error.
Given : 
SE= 4.2
Now, the confidence interval for mean difference will be :-
Hence, the required confidence interval : (13.4996, 32.5004)
Answer: 91
Step-by-step explanation:
Given : The number of documentaries = 5
The number of comedies = 7
The number of mysteries = 4
The number of horror films =5
The total number of movies other than comedy = 14
Now, the number of possible combinations of 9 movies can he rent if he wants all 7 comedies is given by :-
Therefore, the number of possible combinations of 9 movies can he rent if he wants all 7 comedies is 91 .
Answer:
2.39 x 10^5 miles
Step-by-step explanation:
Although it is not usually written, there is always a .0 at the end of a number unless there is a specific decimal that was given.
So, the number here is 239,000.0 and if you count the number of spaces that the decimal needs to move in order to be in the correct spot for scientific notation (which is always after the first number), there is 5 spaces.
Therefore the answer is 2.39 x 10^5 miles.
Answer: 7(5+6)
Step-by-step explanation:
The greatest common factor is the largest number that can both be divisible by 35 and 42
The distributive property is where a number is distributed to both numerals in the equation
