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sleet_krkn [62]
3 years ago
12

Explain your answer !! Have a nice day

Mathematics
2 answers:
exis [7]3 years ago
7 0
(-3,-1) -3(2.5y-0.5)+2y=7
mash [69]3 years ago
4 0

Answer:

(-3,-1)

Step-by-step explanation:

you can solve this by using elimination.

make the first equation in terms of x by adding 5y to each side and dividing by 2. this will give you x= 2.5y - 0.5.

now substitute this equation into the second one. this will give you:

-3(2.5y - 0.5) + 2y = 7

you solve this for y which will give you y = -1

now that you have the y value you can substitute this in the first equation to get: 2x - 5(-1) = -1

you solve this for x which will give you x = -3

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What does change mean in math PLEASE HELP AND ANSWER RIGHT AWAY IF YOU AVAILABLE
Mazyrski [523]

Answer:

"The mean is the average of the numbers: a calculated "central" value of a set of numbers. To calculate it: add up all the numbers, then divide by how many numbers there are." -- Math is Fun


4 0
3 years ago
0.15, 0.17, 0.19.<br><br> what is going up by ?
Tpy6a [65]

Answer:

It goes up by 2 each time

Step-by-step explanation:

3 0
3 years ago
A ladder is leaning against a wall. The top of the ladder is 9 feet (ft) above the ground. If the bottom of the ladder is moved
Komok [63]

Step 1

<u>First situation</u>

when a ladder is leaning against a wall

Let

x-------> the distance of the bottom of the ladder from the wall

L-------> the length of the ladder

<u>Find the length of the ladder</u>

Applying the Pythagorean Theorem

L^{2} =x^{2}+ 9^{2} ------> equation 1

Step 2

<u>Second situation</u>

when the ladder will be lying flat on the ground

<u>Find the length of the ladder</u>

In this situation the length of the ladder is equal to

L=x+3

square both sides

L^{2}=(x+3)^{2} ------> equation 2

Step 3

equate equation 1 and equation 2

x^{2}+ 9^{2}=(x+3)^{2}\\x^{2}+81=x^{2} +6x+9\\ 6x=81-9\\6x=72\\x=12\ ft

therefore

<u>the answer is</u>

the length of the ladder is 12\ ft

see the attached figure to better understand the problem

5 0
3 years ago
If z varies directly with the product of x and y(z=k x y) , then z is said to vary jointly with x and y .
Dafna1 [17]

The value of z varies jointly with w and y.

What is the constant of proportion?

A constant of proportion is illustrated as the ratio which relates two given quantities with each other in the relationship of proportion. Constant of proportion is also called constant variation, rate of change, and constant ratio.

Solving for the value of constant of variation

let k be the constant of proportion

When a quantity varies directly with others, then we have a relation, y = kx

Given relation is z = kxy        —-- 1

Also x varies directly with w i.e. x = k'w, where k' is constant of variation for x and w

Using in equation 1, we have,

z = k(k'w)y

z = kk'wy

z = Kwy, where K is constant of variation i.e. K = kk'

It shows that z varies directly with w and y.

Hence, z varies jointly with w and y.

To learn more about the constant of proportion, visit the link:

brainly.com/question/24868934

#SPJ4

5 0
1 year ago
On the grid, sketch a graph to represent
Greeley [361]

Answer:

Please find attached, the required graph created on MS Excel

Step-by-step explanation:

The distance between Sandy's house and the school = 200 m

The number of minutes Sandy talked to her friend for = 10 minutes

The time it took Sandy to return home to pick her homework = 5 minutes

Let <em>x </em>represent Sandy's location she stops to talk to her friend 10 minutes, we have;

The slope of the motion on the graph, m₁ = (x - 0)/(t - 0)

The slope of her motion running home to pick the up her homework, m₂ = (x - 0)/(5 - 0)

Given that t > 5, the slope on trip back home, m₁, is larger than are her initial slope, m₂

Therefore, where x = 125, we have;

The rate at which she returned home = m₂ = (125 m - 0)/(5 min - 0) = 25 m/min

Given that the same rate m₂ is what she used in heading back to school, we have;

The time it takes her to get to school = 200 m/(25 m/min) = 8 minutes

Therefore, whereby it took her 10 minutes to reach point <em>x</em>, we have the following coordinate points on the graph in a tabular form;

\begin{array}{ccc} Time \ (minutes) \ x-axis&&Distance  \ (meters) \ y-axis\\0&&0\\10&&25\\15&&0\\23&&200\end{array}

The plot of the above point is completed using MS Excel as shown in the attached diagram.

7 0
2 years ago
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