6 and 12 are the factors.
Answer:
31. 122
32. 2400 cans
Step-by-step explanation:
31.
fig 1=1
fig 2=10
fig 3=26
fig 4=50
fig 5=82
fig 6=122
32. 520/13=40
40(60)=2400
Answer: 2.4 pounds of the type of nut that sells for $3.00/lb and 4.8 pounds of the type of nut that sells for $5.40/lb would be needed.
Step-by-step explanation:
Let x represent the number of pounds of the type of nut that sells for $3.00/lb that you would need.
Let y represent the number of pounds of the type of nut that sells for $5.40/lb that you would need.
You would like to have 7.2 lbs of a nut mixture. It means that
x + y = 7.2
The mixture would sell for $4.60/lb. It means that the cost of the mixture would be
4.6 × 7.2 = $33.12
This means that
3x + 5.4y = 33.12- - - - - - - - - 1
Substituting x = 7.2 - y Intl equation 1, it becomes
3(7.2 - y) + 5.4y = 33.12
21.6 - 3y + 5.4y = 33.12
- 3y + 5.4y = 33.12 - 21.6
2.4y = 11.52
y = 11.52/2.4
y = 4.8
x = 7.2 - y = 7.2 - 4.8
x = 2.4
Answer:
p = (2k + 1)i + j
q = 25i + (k + 4)j
p . q = 11
Find the dot product of p and q
(2k + 1)(25) + (k + 4) = 11
50k + 25 + k + 4 = 11
51k = -18
k = - 18/51 = –6/17.✅
b) p.q = |p||q|cos∅
p= (2k + 1)i + j = [2(-6/17) + 1)i + j ]= 5/17i + j
|p| = √ (5/17)² + 1²
|p| = √314/ 17 ( The square root doesn't cover the 17) = 1.0424
q = 25i + (k + 4)j = 25i + ( -6/17 + 4)j
q = 25i + 62/17 j
|q| = √ 25² + (62/17)²
= 25.2646
Now applying them to the formula above
We already have p.q = 11 from the question.
11 = (1.0424)(25.2646)Cos∅
11 = 26.3358Cos∅
Cos∅ = 11/26.3358
Cos∅ = 0.4177
∅ = 65.31°.
This should be it.
Hope it helps
To do a two-column proof, you must know the definitions of the terms that are being used. Also, you must know the postulates and theorems you have learned so far. You look at the given information, and using the definitions, postulates, and theorems, you reason in your mind how to go from the given to the conclusion, step by step. You write each step and the accompanying reason that allows you to conclude each step.
